[英]Java - ScriptEngineManager nashorn Math.random does not work
i call the follow function with the functionName "random" and the parameter "1 and 50". 我用函数名“ random”和参数“ 1 and 50”调用跟随函数。
private String callFunction(String functionName, String[] parameter)
throws FileNotFoundException, ScriptException, NoSuchMethodException {
ScriptEngineManager engine = new ScriptEngineManager().getEngineByName("nashorn");
engine.eval(new FileReader(myPath + functionName + ".js"));
Invocable invocable = (Invocable) engine;
Object result;
if (parameter == null) {
result = invocable.invokeFunction(functionName);
} else {
result = invocable.invokeFunction(functionName, parameter);
}
System.out.println(result);
return (String) result;
}
The content of random.js looks like: random.js的内容如下所示:
function random(min, max){
return Math.floor(Math.random() * (max - min +1)) + min;
}
The results are never between 1 and 50. It is always more than 100. 结果永远不会在1到50之间。它总是大于100。
If i use it not in java it works. 如果我不在Java中使用它,它将起作用。 Work math from nashorn/javascript oherwise in java?
在Java中从nashorn / javascript学习数学吗?
UPDATE : 更新 :
My solution is: 我的解决方案是:
private String callFunction(String functionName, String parameter)
throws FileNotFoundException, ScriptException, NoSuchMethodException, ClassCastException {
String result = "";
engine.eval(new FileReader(PropertiesHandler.getFullDynamicValuePath() + functionName + ".js"));
if (parameter == null) {
result = (String) engine.eval(functionName + "();");
} else {
result = (String) engine.eval(functionName + parameter + ";");
}
return (String) result;
}
So i can use parameters with different types. 所以我可以使用不同类型的参数。
I tweaked your example a little bit you can't assign a ScriptEngine
to a ScriptEngineManager
and it's unclear how you're displaying your random values, or how you're calling random
. 我调整你的例子一点点,你无法分配
ScriptEngine
到ScriptEngineManager
和目前还不清楚你如何显示您的随机值,或者你怎么叫random
。 However, this generates 100 random values between 1
and 50
here 但是,这会在
1
到50
之间生成100个随机值
public static void main(String[] ar) {
String script = "function random(min, max) { "
+ "return Math.floor(Math.random() * (max - min + 1)) + min; }";
ScriptEngine engine = new ScriptEngineManager().getEngineByName("nashorn");
try {
engine.eval(script);
for (int i = 0; i < 100; i++) {
engine.eval("print(random(1, 50));");
}
} catch (ScriptException e) {
e.printStackTrace();
}
}
Adding to Elliot's example there must be something wrong with the parameters you are passing in. The following also generates 100 values between 1 and 50. 添加到Elliot的示例中,您传入的参数肯定有问题。以下内容还会生成1到50之间的100个值。
public static void main(String[] ar) {
String script = "function random(min, max) { "
+ "return Math.floor(Math.random() * (max - min + 1)) + min; }";
ScriptEngine engine = new ScriptEngineManager().getEngineByName("nashorn");
Invocable invocable = (Invocable)engine;
try {
engine.eval(script);
for (int i = 0; i < 100; i++) {
Double result = (Double)invocable.invokeFunction("random", 1, 50);
System.out.println(result.intValue());
}
} catch (ScriptException | NoSuchMethodException e) {
e.printStackTrace();
}
}
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