[英]scanf() to 1D array in C
I'm having problems reading user inputs from terminal into my array. 我在从终端读取用户输入到我的数组时遇到问题。
the array 'a' has a dynamic size. 数组“ a”具有动态大小。 The polynomial which is inputted by the user determines the size of the array.
用户输入的多项式确定数组的大小。
once compiled and run: 一旦编译并运行:
Enter the order number:
3
Enter your constant:
-90
Enter coefficient # 0
8
Enter coefficient # 1
4
Enter coefficient # 2
35
Enter coefficient # 3
54
0 8.000000
1 4.000000
2 0.000000
3 0.000000
On the debug lines I'm just reporting the array back to user. 在调试行中,我只是将阵列报告给用户。 For some reasons it returns zero for the second half of the array.
由于某些原因,它在数组的后半部分返回零。 I can't figure out what the problem could be.
我不知道可能是什么问题。 Any help would be greatly appreciated.
任何帮助将不胜感激。
PS. PS。 ignore eval function.
忽略eval函数。
here is the code I'm working on: 这是我正在处理的代码:
//import required libraries
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
// function prptotype
double eval(double a[], double x, int n); //n is max degree
//global variables
int N = 0;//N is the polynomial order
double *a;//array
double x; // constant
//main function
int main()
{
printf("%s\n", "Enter the order number:");
scanf("%d", &N); // user input for the order numbers
while (N < 1) //input debuger
{
printf("%d %s\n%s\n", N,"is NOT a positive and non-zero number", "Enter a positive and non-zero integer:" );
scanf("%d", &N); // user input for the order numbers
}
a = malloc ((N + 1) * sizeof(int));// assigning the array size in respect with user input
printf("%s\n", "Enter your constant:" );
scanf("%lf", &x);// user input for "x" constant
for (int i = 0; i < N + 1; ++i)
{
printf("Enter coefficient # %d\n", i);
scanf ("%lf", &a[i]);
}
/* Debug */
for (int i = 0; i < N + 1; ++i)
{
//a[i] = 0;
printf("%3d%13lf\n", i, a[i]);
}
}
//eval function
double eval(double a[], double x, int n)
{
}
First problem is this - 第一个问题是-
a = malloc ((N + 1) * sizeof(int)); //you allocate for N+1 integers
You don't allocate enough memory(you need to allocate for N+1
double
) . 您没有分配足够的内存(您需要分配
N+1
double
)。 a
is a double *
and you use sizeof(int)
. a
是double *
sizeof(int)
double *
,您可以使用sizeof(int)
。 Correct it to - 更正为-
a = malloc ((N + 1) * sizeof(double));
And thing for printing double
use %f
not %lf
(only for scanf
)- 和打印的东西
double
用途%f
不会%lf
(仅适用于scanf
) -
printf("%3d%13lf\n", i, a[i]); // -> use %f
^^
Note - Don't forget to free
allocated memory. 注意 -不要忘记
free
分配的内存。 And BTW no array in your code . 而且BTW在您的代码中没有数组。
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