如何在python中用字符串替换列表中的整数？

Question

For instance, how would I define a function so that every odd integer in a list is replaced with the string 'odd'? Thanks

list = [10 , 11, 12, 13, 14, 15, 16,]

Intended result

[10, 'odd', 12, 'odd', 14, 'odd', 16]

Answer 1

I feel like you should probably get the solution on your own, but anyway...

result = []
for i in list:
    if i % 2 != 0:
        result.append('odd')
    else:
        result.append(i)

Or, maybe something to push you forward:

def turn_odd(i):
    if i % 2 != 0:
        return 'odd'
    else:
        return i

list = [10 , 11, 12, 13, 14, 15, 16,]
result = map(lambda x: turn_odd(x), list)

Answer 2

一线解决方案可以是：

print [(i,'odd')[i%2] for i in list]

Answer 3

for i in range(len (list)):
    if (list[i] % 2 != 0):
        list[i] = "odd"

Answer 4

You can use list comprehension:

list = [10 , 11, 12, 13, 14, 15, 16]
new_list = [i if i % 2 == 0 else "odd" for i in list]

Here's a good example of how it works: if/else in Python's list comprehension?

Answer 5

First note that list is reserved for the type list in Python, so I will use my_list instead. Then you have three options:

A loop with a conditional

for i in range(0, len(my_list)):
    if (i % 2 != 0):
        my_list[i] = "odd"

List comprehension (same logic as above)

my_list = ["odd" if i % 2 != 0 else my_list[i] for i in range(len(my_list))]

A loop without a conditional

for i in range(1, len(my_list), 2):
     my_list[i] = "odd"