简体   繁体   English

Python - 在标记的多维数组上应用函数

[英]Python - Apply a function over a labeled multidimensional array

I have a numpy array that is labelled using scipy connected component labelling.我有一个使用scipy连接组件标签标记的numpy数组。

import numpy
from scipy import ndimage

a = numpy.zeros((8,8), dtype=numpy.int)
a[1,1] = a[1,2] = a[2,1] = a[2,2] = a[3,1] = a[3,2] = 1
a[5,5] = a[5,6] = a[6,5] = a[6,6] = a[7,5] = a[7,6] = 1 
lbl, numpatches = ndimage.label(a)

I want to apply a custom function (calculation of a specific value) over all labels within the labelled array.我想对标记数组中的所有标签应用自定义函数(计算特定值)。 Similar as for instance the ndimage algebra functions:类似于 ndimage 代数函数:

ndimage.sum(a,lbl,range(1,numpatches+1))

( Which in this case returns me the number of values for each label [6,6] . ) (在这种情况下,它会返回每个标签[6,6]的值数。)

Is there a way to do this?有没有办法做到这一点?

You can pass an arbitrary function to ndimage.labeled_comprehension , which is roughly equivalent to您可以将任意函数传递给ndimage.labeled_comprehension ,大致相当于

[func(a[lbl == i]) for i in index]

Here is the labeled_comprehension -equivalent of ndimage.sum(a,lbl,range(1,numpatches+1)) :这里是labeled_comprehension的换算ndimage.sum(a,lbl,range(1,numpatches+1))

import numpy as np
from scipy import ndimage

a = np.zeros((8,8), dtype=np.int)
a[1,1] = a[1,2] = a[2,1] = a[2,2] = a[3,1] = a[3,2] = 1
a[5,5] = a[5,6] = a[6,5] = a[6,6] = a[7,5] = a[7,6] = 1 
lbl, numpatches = ndimage.label(a)

def func(x):
    return x.sum()

print(ndimage.labeled_comprehension(a, lbl, index=range(1, numpatches+1), 
                                    func=func, out_dtype='float', default=None))
# [6 6]

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM