[英]QTableView doesn't show anything
I am trying to prototype a window with a QTableView
. 我试图用
QTableView
原型化一个窗口。 There isn't yet any database behind it, but there will be at some point. 它背后还没有任何数据库,但在某些时候会有。 I can't get the tableview to show anything.
我无法让tableview显示任何内容。 I get a rectangle with white space.
我得到一个带有空格的矩形。 I've looked at the examples online and seem to be doing everything right, as far as I can tell.
据我所知,我已经在线查看了这些示例,似乎正在做正确的事情。
I set up a QTableView
object with the GUI builder and then added the following code immediately after the call to ui.setupUi(this);
我使用GUI构建器设置了一个
QTableView
对象,然后在调用ui.setupUi(this);
后立即添加了以下代码ui.setupUi(this);
// set up prototype table model to hold dummy data
QSqlTableModel * model = new QSqlTableModel(this);
model->setTable("Errors");
model->setEditStrategy(QSqlTableModel::OnManualSubmit);
model->select();
// set header names
model->setHeaderData(0, Qt::Horizontal, QObject::tr("Error Number"));
model->setHeaderData(1, Qt::Horizontal, QObject::tr("Message"));
model->setHeaderData(2, Qt::Horizontal, QObject::tr("Details"));
// insert a dummy record
{
QSqlRecord record;
QSqlField field1("Errno", QVariant::Int);
field1.setValue(1);
record.insert(0, field1);
QSqlField field2("Msg", QVariant::String);
field2.setValue(QString("Unable to perform snapshot"));
record.insert(1, field2);
QSqlField field3("Details", QVariant::String);
field3.setValue(QString("Unable to perform snapshot. Please try again"));
record.insert(2, field3);
model->insertRecord(0, record);
}
// insert a dummy record
{
QSqlRecord record;
QSqlField field1("Errno", QVariant::Int);
field1.setValue(1);
record.insert(0, field1);
QSqlField field2("Msg", QVariant::String);
field2.setValue(QString("Unable to perform snapshot"));
record.insert(1, field2);
QSqlField field3("Details", QVariant::String);
field3.setValue(QString("Unable to perform snapshot. Please try again"));
record.insert(2, field3);
model->insertRecord(1, record);
}
ui.errMsgsTableView->setEditTriggers(QAbstractItemView::NoEditTriggers);
ui.errMsgsTableView->setModel(model);
ui.errMsgsTableView->show();
Anyone have any suggestions? 有人有什么建议吗? What am I missing?
我错过了什么?
You cannot use a QSqlTableModel
without a database. 没有数据库,您不能使用
QSqlTableModel
。 As a quick workaround, you could connect it to a temporary in-memory sqlite table that literally can be created in two statements. 作为一种快速解决方法,您可以将其连接到临时内存中的sqlite表,该表可以在两个语句中创建。 For prototyping you should probably use a
QStandardItemModel
, though. 但是,对于原型设计,您应该使用
QStandardItemModel
。 Here's a complete example: 这是一个完整的例子:
// https://github.com/KubaO/stackoverflown/tree/master/questions/dummymodel-37577922
#include <QtWidgets>
template <typename T> QStandardItem * newItem(const T val) {
auto item = new QStandardItem;
item->setData(val, Qt::DisplayRole);
return item;
}
int main(int argc, char ** argv) {
QApplication app{argc, argv};
QStandardItemModel model;
model.setColumnCount(3);
model.setHorizontalHeaderLabels(QStringList{"Error Number", "Message", "Details"});
auto newRow = []{ return QList<QStandardItem*>{
newItem(1),
newItem("Unable to perform snapshot"),
newItem("Unable to perform snapshot. Please try again")};
};
model.appendRow(newRow());
model.appendRow(newRow());
QTableView view;
view.setModel(&model);
view.show();
return app.exec();
}
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