python numpy reshape（v.shape）和reshape（* v.shape）之间的区别

Question

I found myself struggled in the following two region of codes(which exactly did the same job),can anyone tell me what the difference?

Code1:

v = np.zeros((2,5))
value_one = np.linspace(-1.4, 1.3, num=v.size).reshape(*v.shape)

Code2:

v = np.zeros((2,5))
value_two = np.linspace(-1.4, 1.3, num=v.size).reshape(v.shape)

Answer 1

Since reshape can accept either ints or tuple of ints both version are ok. You can verify by

value_one = np.linspace(-1.4, 1.3, num=10).reshape(2,5)

value_one = np.linspace(-1.4, 1.3, num=10).reshape((2,5))

The stared version *v.shape will strip the tuple to its elements.