使用.format（）打印一个不超过定义数量的空格并居中的字符串？

Question

So Im trying to do three things here. 1. Get the print statement below to be 16 spaces long 2. Cut off the extra = signs on eiter side of the name that cause it to be longer than 16. 3. Center the text so an equal amount of = signs are either side of the name

This is my attempt...

import random

name_list = ['Joe','Phil','Frank','Daniel']
name_choice = random.choice(name_list)
name_string = '======| {0} |======'.format(name_choice)
print('{0:.16}'.format(name_string))

======| Phil |==  # Result
====| Phil |==== # What I want

Answer 1

You can define a function that will return your desired output:

def heading(text):
    return '{0:=^16}'.format(text)
heading(name_choice)

Please note that if one of the names in the list is longer than 16 characters, this function will return the entire name, without = signs.

Answer 2

您应该更改print('{0:.16}'.format(name_string))以print('{0:16}'.format(name_string)) ，然后它将起作用。

Answer 3

Adding | {0} | | {0} | to the formatting in simon.sim's answer produces the OP's desired ouput shown in the question:

import random

def extra_format(text):
    return '{0:=^16}'.format(text)

name_list = ['Joe','Phil','Frank','Daniel']
name_choice = random.choice(name_list)
print(extra_format('| {0} |'.format(name_choice))) # ====| Phil |==== # What I want