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如何根据相关性生成分组变量?

[英]how to generate grouping variable based on correlation?

 library(magrittr)
 library(dplyr)
 V1 <- c("A","A","A","A","A","A","B","B","B","B", "B","B","C","C","C","C","C","C","D","D","D","D","D","D","E","E","E","E","E","E")
 V2 <- c("A","B","C","D","E","F","A","B","C","D","E","F","A","B","C","D","E","F","A","B","C","D","E","F","A","B","C","D","E","F")
 cor <- c(1,0.8,NA,NA,NA,NA,0.8,1,NA,NA,NA,NA,NA,NA,1,0.8,NA,NA,NA,NA,0.8,1,NA,NA,NA,NA,NA,NA,1,0.9)


 df <- data.frame(V1,V2,cor)

 # exclude rows where cor=NA
 df <- df[complete.cases(df)==TRUE,]

This is the full data frame, cor=NA represents a correlation smaller than 0.8 这是完整的数据帧,cor = NA表示小于0.8的相关性

 df

   V1 V2 cor
1   A  A 1.0
2   A  B 0.8
7   B  A 0.8
8   B  B 1.0
15  C  C 1.0
16  C  D 0.8
21  D  C 0.8
22  D  D 1.0
29  E  E 1.0
30  E  F 0.9

In the above df, F is not in V1, meaning that F is not of interest 在上面的df中,F不在V1中,这意味着F不重要

so here I remove rows where V2=F (more generally, V2 equals to value that is not in V1) 所以在这里我删除了V2 = F的行(通常,V2等于不在V1中的值)

 V1.LIST <- unique(df$V1)
 df.gp <- df[which(df$V2 %in% V1.LIST),]

 df.gp

   V1 V2 cor
1   A  A 1.0
2   A  B 0.8
7   B  A 0.8
8   B  B 1.0
15  C  C 1.0
16  C  D 0.8
21  D  C 0.8
22  D  D 1.0
29  E  E 1.0

So now, df.gp is the dataset I need to work on 所以现在,df.gp是我需要处理的数据集

I drop the unused level in V2 (which is F in the example) 我在V2中删除了未使用的级别(在示例中为F)

 df.gp$V2 <- droplevels(df.gp$V2)

I do not want to exclude the autocorrelated variables, in case some of the V1 are not correlated with others, and I would like to put each of them in a separated group 我不想排除自相关变量,以防某些V1与其他变量不相关,并且我想将每个变量放在一个单独的组中

By looking at the cor, A and B are correlated, C and D are correalted, and E belongs to a group by itself. 通过查看cor,可以将A和B关联起来,将C和D关联起来,而E本身属于一个组。

Therefore, the example here should have three groups. 因此,此处的示例应分为三组。

The way I see this, you may have complicated things by working your data straight into a data.frame . 我认为,将数据直接处理为data.frame可能会使事情复杂化。 I took the liberty of transforming it back to a matrix. 我自由地将其转换回矩阵。

library(reshape2)
cormat <- as.matrix(dcast(data = df,formula = V1~V2))[,-1]
row.names(cormat) <- colnames(cormat)[-length(colnames(cormat))]
cormat

After I had your correlation matrix, it is easy to see which indices or non NA values are shared with other variables. 获得相关矩阵后,可以轻松查看与其他变量共享哪些索引或非NA值。

a <- apply(cormat, 1, function(x) which(!is.na(x)))
a <- data.frame(t(a))
a$var <- row.names(a)
row.names(a) <- NULL
a

  X1 X2 var
1  1  2   A
2  1  2   B
3  3  4   C
4  3  4   D
5  5  6   E

Now either X1 or X2 determines your unique groupings. 现在, X1X2确定您的唯一分组。

Edited by cyrusjan: cyrusjan编辑:

The above script is a possible solution when assuming we already select the rows in with cor >= a , where a is a threshold taken as 0.8 in the above question. 假设我们已经选择了cor >= a的行,则上述脚本是一种可能的解决方案,其中a是上述问题中的阈值为0.8。

Contributed by alexis_laz: 由alexis_laz贡献:

By using cutree and hclust , we can set the threshold in the script (ie h=0.8) as blow. 通过使用cutreehclust ,我们可以将脚本中的阈值(即h = 0.8)设置为打击。

 cor.gp <- data.frame(cor.gp =
      cutree(hclust(1 - as.dist(xtabs(cor ~ V1 + V2, df.gp))), h = 0.8))

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