简体   繁体   English

如何应用按位运算符来比较对象列表

[英]How to apply bitwise operator to compare a list of objects

Suppose I have a long list of objects (say, a list of numpy matrices of bool elements) foo = [a, b, c] , that I want to compare with some bitwise operator, to get something like a | b | c假设我有一个很长的对象列表(例如,bool 元素的 numpy 矩阵列表) foo = [a, b, c] ,我想与一些按位运算符进行比较,以获得类似a | b | c a | b | c a | b | c . a | b | c

If I could use this bitwise operation as a function, say a bitwiseor function, I could simply do this with bitwiseor(*foo) .如果我可以使用这个按位运算作为一个函数,比如说一个bitwiseor函数,我可以简单地用bitwiseor(*foo)来做到这一点。 However, I was not able to find whether the bitwise or can be written in such functional form.但是,我无法找到是否可以按位或以这种函数形式编写。

Is there some handy way to handle this kind of problem?有没有一些方便的方法来处理这种问题? Or should I just use a loop to compare all the elements cumulatively?或者我应该只使用循环来累积比较所有元素?

Using the functional method in operator in combination withfunctools.reduce :结合functools.reduce使用operator中的函数方法:

>>> import operator, functools
>>> functools.reduce(operator.or_, [1, 2, 3])
3

numpy has a number of functions that support reducing along an axis. numpy有许多支持沿轴减少的函数。 See numpy.bitwise_or and numpy.bitwise_or.reduce .请参阅numpy.bitwise_ornumpy.bitwise_or.reduce

np.bitwise_or.reduce(your_array)

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM