[英]Nested list comprehension where inner loop range is dependent on outer loop
I am trying to represent the following as a list comprehension: 我试图将以下内容表示为列表理解:
L = []
for x in range(n):
for y in range(x):
L.append( (x, y) )
I have done nested list comprehension in the more typical matrix scenario where the inner loop range is not dependent on the outer loop. 我已经在更典型的矩阵方案中完成了嵌套列表理解,在这种方案中,内部循环范围不取决于外部循环。
I have considered there may be solutions in itertools
, using product()
or chain()
but have been unsuccessful there as well. 我考虑过
itertools
可能有解决方案,使用product()
或chain()
但在那里也没有成功。
Remember to wrap the x, y
in parentheses this is the only slight caveat that if omitted leads to a SyntaxError
. 请记住,将
x, y
括在括号中,这是唯一的警告,如果省略会导致SyntaxError
。
Other than that, the translation is pretty straightforward; 除此之外,翻译非常简单。 the order of the
for
s inside the comprehension is similar to that with the nested statements: 理解中
for
的顺序类似于嵌套语句的顺序:
n = 5
[(x, y) for x in range(n) for y in range(x)]
Yields similar results to its nested loop counterpart: 产生与其嵌套循环副本类似的结果:
[(1, 0),
(2, 0),
(2, 1),
(3, 0),
(3, 1),
(3, 2),
(4, 0),
(4, 1),
(4, 2),
(4, 3)]
Below is the example to convert your code to list comprehension. 下面是将代码转换为列表理解的示例。
>>> n = 10
>>> [ (x,y) for x in range(n) for y in range(x)]
[(1, 0), (2, 0), (2, 1), (3, 0), (3, 1), (3, 2), (4, 0), (4, 1), (4, 2), (4, 3), (5, 0), (5, 1), (5, 2), (5, 3), (5, 4), (6, 0), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (7, 0), (7, 1), (7, 2), (7, 3), (7, 4), (7, 5), (7, 6), (8, 0), (8, 1), (8, 2), (8, 3), (8, 4), (8, 5), (8, 6), (8, 7), (9, 0), (9, 1), (9, 2), (9, 3), (9, 4), (9, 5), (9, 6), (9, 7), (9, 8)]
Alternatively, you achieve the same result using itertools
library (sharing it just for your knowledge info, but is not recommended for this problem statement): 另外,您可以使用
itertools
库获得相同的结果(仅为您的知识信息而共享它,但不建议对此问题语句进行共享):
>>> import itertools
>>> list(itertools.chain.from_iterable(([(list(itertools.product([x], range(x)))) for x in range(n)])))
[(1, 0), (2, 0), (2, 1), (3, 0), (3, 1), (3, 2), (4, 0), (4, 1), (4, 2), (4, 3), (5, 0), (5, 1), (5, 2), (5, 3), (5, 4), (6, 0), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (7, 0), (7, 1), (7, 2), (7, 3), (7, 4), (7, 5), (7, 6), (8, 0), (8, 1), (8, 2), (8, 3), (8, 4), (8, 5), (8, 6), (8, 7), (9, 0), (9, 1), (9, 2), (9, 3), (9, 4), (9, 5), (9, 6), (9, 7), (9, 8)]
List comprehensions are designed to make a straightforward translation of that loop possible: 列表推导旨在使该循环的直接翻译成为可能:
[ (x,y) for x in range(3) for y in range(x) ]
Is that not what you wanted? 那不是你想要的吗?
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