pyspark：NameError：未定义名称'spark'

Question

I am copying the pyspark.ml example from the official document website: http://spark.apache.org/docs/latest/api/python/pyspark.ml.html#pyspark.ml.Transformer

data = [(Vectors.dense([0.0, 0.0]),), (Vectors.dense([1.0, 1.0]),),(Vectors.dense([9.0, 8.0]),), (Vectors.dense([8.0, 9.0]),)]
df = spark.createDataFrame(data, ["features"])
kmeans = KMeans(k=2, seed=1)
model = kmeans.fit(df)

However, the example above wouldn't run and gave me the following errors:

---------------------------------------------------------------------------
NameError                                 Traceback (most recent call last)
<ipython-input-28-aaffcd1239c9> in <module>()
      1 from pyspark import *
      2 data = [(Vectors.dense([0.0, 0.0]),), (Vectors.dense([1.0, 1.0]),),(Vectors.dense([9.0, 8.0]),), (Vectors.dense([8.0, 9.0]),)]
----> 3 df = spark.createDataFrame(data, ["features"])
      4 kmeans = KMeans(k=2, seed=1)
      5 model = kmeans.fit(df)

NameError: name 'spark' is not defined

What additional configuration/variable needs to be set to get the example running?

Answer 1

You can add

from pyspark.context import SparkContext
from pyspark.sql.session import SparkSession
sc = SparkContext('local')
spark = SparkSession(sc)

to the begining of your codes to define a SparkSession, then the spark.createDataFrame() should work.

Answer 2

Since you are calling createDataFrame() , you need to do this:

df = sqlContext.createDataFrame(data, ["features"])

instead of this:

df = spark.createDataFrame(data, ["features"])

spark stands there as the sqlContext .

---

In general, some people have that as sc , so if that didn't work, you could try:

df = sc.createDataFrame(data, ["features"])

Answer 3

Answer by 率怀一 is good and will work for the first time. But the second time you try it, it will throw the following exception :

ValueError: Cannot run multiple SparkContexts at once; existing SparkContext(app=pyspark-shell, master=local) created by __init__ at <ipython-input-3-786525f7559f>:10 

There are two ways to avoid it.

1) Using SparkContext.getOrCreate() instead of SparkContext() :

from pyspark.context import SparkContext
from pyspark.sql.session import SparkSession
sc = SparkContext.getOrCreate()
spark = SparkSession(sc)

2) Using sc.stop() in the end, or before you start another SparkContext.

Answer 4

If it errors you regarding other open session do this:

from pyspark.context import SparkContext
from pyspark.sql.session import SparkSession
sc = SparkContext.getOrCreate();

spark = SparkSession(sc)
scraped_data=spark.read.json("/Users/reihaneh/Desktop/nov3_final_tst1/")

Answer 5

如果您使用 python，则必须按以下方式导入 spark，然后它将创建一个 spark 会话，但请记住这是一种旧方法，尽管它会起作用。

from pyspark.shell import spark