在 Swift 3 中用 UnsafeMutablePointer 编写

Question

The code below was working in previous versions of Swift, now compiler rejects it. I need this function to interop with Swift from ObjectiveC.

@objc public static func myFunc(jdUT: Double, _ lon: Double, _ lat: Double,
                                           _ dayLen: Double, _ SbhDeg: Double, _ MgrbDeg: Double,
                                           omsk: UnsafeMutablePointer<Double>)
    {
        var z = somefuncion()
        // this line gives this error : Cannot assign to property: 'omsk' is a 'let' constant
        omsk.memory=z;
    }

Answer 1

The error message is misleading. The memory property of Unsafe(Mutable)Pointer has been renamed to pointee in Swift 3:

let z = someFunction()
omsk.pointee = z

Answer 2

@objc public static func myFunc(jdUT: Double, _ lon: Double, _ lat: Double,
                                       _ dayLen: Double, _ SbhDeg: Double, _ MgrbDeg: Double,
                                       inout omsk: UnsafeMutablePointer<Double>)
{
    var z = somefuncion()
    // this line gives this error : Cannot assign to property: 'omsk' is a 'let' constant
    omsk.memory=z;
}

Adding inout before the omsk parameter should work.