[英]how to display data in one page from different database table
i have database that having 2 table which is event , venue. 我有2个表是活动,场地的数据库。
the event table hold eventTitle , eventID and venueID. 事件表包含eventTitle,eventID和venueID。
the venue table hold venueID , venueName and location. 场地表持有场地ID,场地名称和位置。
this is my sql query . 这是我的SQL查询。
$sqlEvent = "SELECT * FROM te_events , te_venue ORDER by eventTitle
WHERE te_events.venueID = te_venue.venueID
";
but there is an error u have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'WHERE te_events.venueID = te_venue.venueID' at line 2
但是有u have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'WHERE te_events.venueID = te_venue.venueID' at line 2
u have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'WHERE te_events.venueID = te_venue.venueID' at line 2
what i want to do is display the venuename and location in the page by using php script. 我想要做的是使用PHP脚本在页面中显示venuename和位置。 after i remove 'where' clause, everything works find but the event is repeated. 删除'where'子句后,一切正常,但事件会重复。
Wrong clause where sequence 错误的子句在哪里顺序
"SELECT * FROM te_events , te_venue
WHERE te_events.venueID = te_venue.venueID
ORDER by eventTitle ";
In a select the where clasue is before the order by 在选择where clasue在order by之前
$sqlEvent = "SELECT * FROM te_events , te_venue WHERE te_events.venueID = te_venue.venueID ORDER by eventTitle ";
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