如何在不同数据库表的一个页面中显示数据

Question

我有2个表是活动，场地的数据库。
事件表包含eventTitle，eventID和venueID。
场地表持有场地ID，场地名称和位置。
这是我的SQL查询。

$sqlEvent = "SELECT * FROM te_events , te_venue ORDER by eventTitle
                WHERE te_events.venueID = te_venue.venueID
                 ";

但是有u have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'WHERE te_events.venueID = te_venue.venueID' at line 2 u have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'WHERE te_events.venueID = te_venue.venueID' at line 2
我想要做的是使用PHP脚本在页面中显示venuename和位置。 删除'where'子句后，一切正常，但事件会重复。

Answer 1

错误的子句在哪里顺序

"SELECT * FROM te_events , te_venue 
  WHERE te_events.venueID = te_venue.venueID
ORDER by eventTitle  ";

在选择where clasue在order by之前

Answer 2

$sqlEvent = "SELECT * FROM te_events , te_venue WHERE te_events.venueID = te_venue.venueID ORDER by eventTitle  ";