如何在不同數據庫表的一個頁面中顯示數據

Question

我有2個表是活動，場地的數據庫。
事件表包含eventTitle，eventID和venueID。
場地表持有場地ID，場地名稱和位置。
這是我的SQL查詢。

$sqlEvent = "SELECT * FROM te_events , te_venue ORDER by eventTitle
                WHERE te_events.venueID = te_venue.venueID
                 ";

但是有u have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'WHERE te_events.venueID = te_venue.venueID' at line 2 u have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'WHERE te_events.venueID = te_venue.venueID' at line 2
我想要做的是使用PHP腳本在頁面中顯示venuename和位置。 刪除'where'子句后，一切正常，但事件會重復。

Answer 1

錯誤的子句在哪里順序

"SELECT * FROM te_events , te_venue 
  WHERE te_events.venueID = te_venue.venueID
ORDER by eventTitle  ";

在選擇where clasue在order by之前

Answer 2

$sqlEvent = "SELECT * FROM te_events , te_venue WHERE te_events.venueID = te_venue.venueID ORDER by eventTitle  ";