如何遍历“pyspark”中的列表列表以获得特定结果

Question

I am new to PySpark, I am trying to understand how I can do this. Any help appreciated.

I have this RDD for example :

[[u'merit', u'release', u'appearance'], [u'www.bonsai.wbff.org'], [u'whitepages.com'], [u'the', u'childs', u'wonderland', u'company'], [u'lottery']]

I try to have :

[[(u'merit',1), (u'release',1), (u'appearance',1)], [(u'www.bonsai.wbff.org',1)], [(u'whitepages.com',1)], [(u'the',1), (u'childs',1), (u'wonderland',1), (u'company',1)], [(u'lottery',1)]] 

But all I've tried, it gets me either this result :

[[u'merit', u'release', u'appearance',1], [u'www.bonsai.wbff.org',1], [u'whitepages.com',1], [u'the', u'childs', u'wonderland', u'company',1], [u'lottery',1]]

or these errors:

• TypeError: 'PipelinedRDD' object is not iterable
• AttributeError: 'list' object has no attribute 'foreach' - or split , take , etc.

I tried this :

rdd1=rdd.map(lambda r : (r,1))  

I have the first result :

[u'merit', u'release', u'appearance',1], [u'www.bonsai.wbff.org',1], [u'whitepages.com',1], [u'the', u'childs', u'wonderland', u'company',1], [u'lottery',1]]

rdd1=rdd.map(lambda r : (r[:][0],1))  

It gets just the first word in each line, it's not what I want

for row in rdd.collect() : row.foreach(lambda x : (x,1)) 
# AttributeError: 'list' object has no attribute 'foreach'

rdd3.take(100).foreach( lambda a : (a.foreach( lambda e : print(e,1)))) 
# AttributeError: 'list' object has no attribute 'foreach'

Answer 1

To print collect and iterate locally:

for xs in rdd3.take(100):
    for x in xs:
        print(x)

To iterate in general:

rdd.flatMap(lambda xs: [(x, 1) for x in xs])