简体   繁体   English

增强Java代码以提高效率

[英]enhancing java code to be more efficient

I am trying to expand a GWT tree using selenium and i did successfully with that code 我正在尝试使用硒扩展GWT树,并且我成功地使用了该代码

for (int i = 0; i < elem.size(); i++) {
 if (!elem.get(i).isExpanded() || !elem.get(i).isLeaf()) {
  elem.get(i).toggleExpand();
 }
 for (int j = 0; j < elem.get(i).getChildren().size(); j++) {
  if (!elem.get(i).getChildren().get(j).isExpanded() || 
                        !elem.get(i).getChildren().get(j).isLeaf()) {
   elem.get(i).getChildren().get(j).toggleExpand();
  }
  for (int k = 0; k < elem.get(i).getChildren().get(j).getChildren().size(); k++) {
   if (!elem.get(i).getChildren().get(j).getChildren().get(k).isExpanded() ||
              !elem.get(i).getChildren().get(j).getChildren().get(k).isLeaf()) {
    elem.get(i).getChildren().get(j).getChildren().get(k).toggleExpand();
   }.....
  }
 }
}

My question is how to enhance that code or how to put in recursive method ? 我的问题是如何增强该代码或如何放入递归方法?

To make that code more readable there are a few things you could do (: 为了使代码更具可读性,您可以做一些事情(:

Reuse method results, eg that of elem.get(i) or use an extended for-loop (if elem etc. support that): 重用方法结果,例如elem.get(i)结果,或使用扩展的for循环(如果elem等支持):

for (int i = 0; i < elem.size(); i++) {
  ElementClass element = elem.get(i);
  if (!element.isExpanded() || !element.isLeaf()) {
    element.toggleExpand();
  }

  ...
}

Additionally since you seem to do the same for the element and it's children you could provide a method eg: 另外,由于您似乎对元素及其子元素都执行相同的操作,因此可以提供一种方法,例如:

public void expandIfNeeded(ElementClass element) {
  if (!element.isExpanded() || !element.isLeaf()) {
    element.toggleExpand();
  }
}

Then you loop could look like this: 然后,循环看起来像这样:

for (int i = 0; i < elem.size(); i++) {
  ElementClass element = elem.get(i);
  expandIfNeeded( element );

  ... //handle children here and call the same method for those (could also be using recursion)
}

Additionally, if you don't need the index i and elem is iterable you could use the extended for: 另外,如果您不需要索引i并且elem是可迭代的,则可以将扩展名用于:

for ( ElementClass element : elem ) {
  expandIfNeeded( element );

  ... //handle children here and call the same method for those (could also be using recursion)
}

And of course recursion would make it more readable, especially if you don't know the depth of the tree: 当然,递归将使其更具可读性,尤其是在您不知道树的深度的情况下:

//I'm assuming "elem" is a List<ElementClass> here
public void expandElements( List<ElementClass> elem ) {
  for ( ElementClass element : elem ) {
    expandIfNeeded( element );
    expandElements( element.getChildren() );
  }
}

Unreadable code. 无法读取的代码。

Try something like this: 尝试这样的事情:

for (int i = 0; i < elem.size(); i++) {
  if (!elem.get(i).isExpanded()) {
    elem.get(i).toggleExpand();
  }
  // I don't know what this method returns; no time to research for you
  List<Element> children = elem.get(i).getChildren();
  for (int j = 0; j < children.size(); j++) {
      // don't know what you call it; must be a void method of some kind
      yourMethodName(children.get(i));
  }
}

You can recursively toggled the element by using following code. 您可以使用以下代码来递归切换元素。

public static void toggleElement(Element elem){

        if(elem.isExpand() || elem.isLeaf()){
            return;
        }else{
            elem.toggledExpand();
        }
        List<Element> children=elem.getChildren();
        for (int i = 0; i < children.size(); i++) {
            toggleElement(children.get(i));
        }
    }

Hopefully it will resolve your problem. 希望它能解决您的问题。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM