Sequelize - 不区分大小写，如

Question

How can I achieve this in Sequelize?

SELECT * FROM table where lower(column) LIKE ('abcd%');

I can't find a way to mix lower function with $like

Answer 1

You should use Sequelize.Op :

Table.findAll({
    where: {
        name: {
            [Sequelize.Op.iLike]: searchQuery
        }
    }
})

Don't forget to add % before or after your searchQuery, if you want to make a partial query.

See the docs here

Answer 2

I found the solution:

Table.findAll({
  attributes: ['createdAt', 'col'],
  where: {
    $and:[
      {
        createdAt:{
          $between:[minDate, maxDate]
        }
      },
      Sequelize.where(
        Sequelize.fn('lower', Sequelize.col('col')),
        {
          $like: 'abcd%'
        }
      )
    ]
  }
});

Answer 3

If you're using PostGres, you can use the $iLike operator to search rows (NOT column names like your question asks).

Sequelize Docs

While it doesn't fully address your question, hopefully it will help someone down the road who searches for case-insensitive + Sequelize, which brought me here.

Table.findAll({
    where: {
        createdAt: {
            $between: [minDate, maxDate]
        },
        someOtherColumn: {
            $like: '%mysearchterm%'
        }
    }
})

Answer 4

I run into similar problem and solved by

const values = ['adcd'].map(x => x.toLowerCase());

const results = await SomeModel.findAll({
   attributes: [
      ...Object.keys(SomeModel.rawAttributes),
      [Sequelize.fn('LOWER', Sequelize.col('someColumn')), 'lower'],
   ],
   having: { lower: values, },
});