如何在pyspark.sql中创建一个表作为select

Question

Is it possible to create a table on spark using a select statement?

I do the following

import findspark
findspark.init()
import pyspark
from pyspark.sql import SQLContext

sc = pyspark.SparkContext()
sqlCtx = SQLContext(sc)

spark_df = sqlCtx.read.format('com.databricks.spark.csv').options(header='true', inferschema='true').load("./data/documents_topics.csv")
spark_df.registerTempTable("my_table")

sqlCtx.sql("CREATE TABLE my_table_2 AS SELECT * from my_table")

but I get the error

/Users/user/anaconda/bin/python /Users/user/workspace/Outbrain-Click-Prediction/test.py Using Spark's default log4j profile: org/apache/spark/log4j-defaults.properties Setting default log level to "WARN". To adjust logging level use sc.setLogLevel(newLevel). 17/01/21 17:19:43 WARN NativeCodeLoader: Unable to load native-hadoop library for your platform... using builtin-java classes where applicable Traceback (most recent call last): File "/Users/user/spark-2.0.2-bin-hadoop2.7/python/pyspark/sql/utils.py", line 63, in deco return f(*a, **kw) File "/Users/user/spark-2.0.2-bin-hadoop2.7/python/lib/py4j-0.10.3-src.zip/py4j/protocol.py", line 319, in get_return_value py4j.protocol.Py4JJavaError: An error occurred while calling o19.sql. : org.apache.spark.sql.AnalysisException: unresolved operator 'CreateHiveTableAsSelectLogicalPlan CatalogTable( Table: my_table_2 Created: Sat Jan 21 17:19:53 EST 2017 Last Access: Wed Dec 31 18:59:59 EST 1969 Type: MANAGED Storage(InputFormat: org.apache.hadoop.mapred.TextInputFormat, OutputFormat: org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat)), false;; 'CreateHiveTableAsSelectLogicalPlan CatalogTable( Table: my_table_2 Created: Sat Jan 21 17:19:53 EST 2017 Last Access: Wed Dec 31 18:59:59 EST 1969 Type: MANAGED Storage(InputFormat: org.apache.hadoop.mapred.TextInputFormat, OutputFormat: org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat)), false : +- Project [document_id#0, topic_id#1, confidence_level#2] : +- SubqueryAlias my_table : +- Relation[document_id#0,topic_id#1,confidence_level#2] csv

at org.apache.spark.sql.catalyst.analysis.CheckAnalysis$class.failAnalysis(CheckAnalysis.scala:40) at org.apache.spark.sql.catalyst.analysis.Analyzer.failAnalysis(Analyzer.scala:58) at org.apache.spark.sql.catalyst.analysis.CheckAnalysis$$anonfun$checkAnalysis$1.apply(CheckAnalysis.scala:374) at org.apache.spark.sql.catalyst.analysis.CheckAnalysis$$anonfun$checkAnalysis$1.apply(CheckAnalysis.scala:67) at org.apache.spark.sql.catalyst.trees.TreeNode.foreachUp(TreeNode.scala:126) at org.apache.spark.sql.catalyst.analysis.CheckAnalysis$class.checkAnalysis(CheckAnalysis.scala:67) at org.apache.spark.sql.catalyst.analysis.Analyzer.checkAnalysis(Analyzer.scala:58) at org.apache.spark.sql.execution.QueryExecution.assertAnalyzed(QueryExecution.scala:49) at org.apache.spark.sql.Dataset$.ofRows(Dataset.scala:64) at org.apache.spark.sql.SparkSession.sql(SparkSession.scala:582) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMetho dAccessorImpl.java:62) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:498) at py4j.reflection.MethodInvoker.invoke(MethodInvoker.java:237) at py4j.reflection.ReflectionEngine.invoke(ReflectionEngine.java:357) at py4j.Gateway.invoke(Gateway.java:280) at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:132) at py4j.commands.CallCommand.execute(CallCommand.java:79) at py4j.GatewayConnection.run(GatewayConnection.java:214) at java.lang.Thread.run(Thread.java:745)

During handling of the above exception, another exception occurred:

Traceback (most recent call last): File "/Users/user/workspace/Outbrain-Click-Prediction/test.py", line 16, in sqlCtx.sql("CREATE TABLE my_table_2 AS SELECT * from my_table") File "/Users/user/spark-2.0.2-bin-hadoop2.7/python/pyspark/sql/context.py", line 360, in sql return self.sparkSession.sql(sqlQuery) File "/Users/user/spark-2.0.2-bin-hadoop2.7/python/pyspark/sql/session.py", line 543, in sql return DataFrame(self._jsparkSession.sql(sqlQuery), self._wrapped) File "/Users/user/spark-2.0.2-bin-hadoop2.7/python/lib/py4j-0.10.3-src.zip/py4j/java_gateway.py", line 1133, in call File "/Users/user/spark-2.0.2-bin-hadoop2.7/python/pyspark/sql/utils.py", line 69, in deco raise AnalysisException(s.split(': ', 1)[1], stackTrace) pyspark.sql.utils.AnalysisException: "unresolved operator 'CreateHiveTableAsSelectLogicalPlan CatalogTable(\\n\\tTable: my_table_2 \\n\\tCreated: Sat Jan 21 17:19:53 EST 2017\\n\\tLast Access: Wed Dec 31 18:59:59 EST 1969\\n\\tType: MANAGED\\n\\tStorage(InputFormat: org.apache. hadoop.mapred.TextInputFormat, OutputFormat: org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat)), false;;\\n'CreateHiveTableAsSelectLogicalPlan CatalogTable(\\n\\tTable: my_table_2 \\n\\tCreated: Sat Jan 21 17:19:53 EST 2017\\n\\tLast Access: Wed Dec 31 18:59:59 EST 1969\\n\\tType: MANAGED\\n\\tStorage(InputFormat: org.apache.hadoop.mapred.TextInputFormat, OutputFormat: org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat)), false\\n: +- Project [document_id#0, topic_id#1, confidence_level#2]\\n: +- SubqueryAlias my_table\\n: +- Relation[document_id#0,topic_id#1,confidence_level#2] csv\\n"

Answer 1

I've corrected this issue by using HiveContext instead of SQLContext as below:

import findspark
findspark.init()
import pyspark
from pyspark.sql import HiveContext

sqlCtx= HiveContext(sc)

spark_df = sqlCtx.read.format('com.databricks.spark.csv').options(header='true', inferschema='true').load("./data/documents_topics.csv")
spark_df.registerTempTable("my_table")

sqlCtx.sql("CREATE TABLE my_table_2 AS SELECT * from my_table")

Answer 2

您应首先进行选择并将其分配给数据帧变量，然后将其与registerTempTable一起registerTempTable就像使用CSV文件创建的数据帧一样