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如何使用 matplotlib 绘制数组中的特定点?

[英]How to plot specific points in array with matplotlib?

I generated two arrays with 10 different values.我生成了两个具有 10 个不同值的数组。 How do I plot 3 specific values within each array using matplotlib?如何使用 matplotlib 在每个数组中绘制 3 个特定值? Here is my code so far:到目前为止,这是我的代码:

import numpy as np
import matplotlib as plt
x = np.array(1,2,3,4,5,6,7,8,9,10)
y = np.array(1,2,3,4,5,6,7,8,9,10)

I only want to plot the points 3,4,5 of the x-array and it's corresponding y values.我只想绘制 x 数组的 3,4,5 点及其对应的 y 值。 I have tried this:我试过这个:

plt.plot(x[2,3,4], y[2,3,4])
plt.show()

But I get the error "too many indices for array."但是我收到错误“数组的索引太多”。 However, if I write但是,如果我写

plt.plot(x[2], y[2])
plt.show()

the second element in the arrays will plot.将绘制数组中的第二个元素。

The problem is the syntax of x[3, 4, 5] .问题是x[3, 4, 5]的语法。 It is wrong what you want to do is x[3] , x[4] , x[5] , which are the respective elements of the array.您想要做的是x[3]x[4]x[5] ,它们是数组的各个元素。

print(x[3], x[4], x[5]) # print 4, 5, 6

A more comfortable way to do this is:一种更舒适的方法是:

plt.plot(x[2:5], y[2:5])
plt.show()

Where x[2:5] returns from the third to the fifth element.其中x[2:5]从第三个元素返回到第五个元素。

As Tony Tannous says, the creation of the array is also wrong.正如Tony Tannous所说,数组的创建也是错误的。 np.array needs a list! np.array需要一个列表!

Then you also have to change the creation of x and y:然后你还必须改变 x 和 y 的创建:

x = np.array([1,2,3,4,5,6,7,8,9,10])
y = np.array([1,2,3,4,5,6,7,8,9,10])

Adding [ and ] to make it a list.添加[]使其成为列表。

Surely you should see the documentation of Indexing当然你应该看到索引的文档

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