r的最新版本的位置

Question

I have 5 variables. I want to Create one variable which has the latest version.

For Example.

Version10 Version 8 Version9 Version 5 version1  expected Output
  1         1          0         0        0      Version10
  0        0            1       1        0       Version9
  0          1         1        1         1      Version8
  0          0          0        0        1       version1      

I tried with following syntax but getting an error.

df<-data.frame(cbind(Version10,Version9,Version8,Version5,Version1))

for (i in 1:5) {
if (maxvalue==df(I) {
maxvar<-i
maxcount<-maxcount+1 }

Please suggest.

Thanks Tanuvi

Answer 1

we can use max.col to find the index of the max value in each row, if there are multiple max values, then use the ties.method = "first" . subset the column names based on the index and create a new column

df1$expectedOutput <- names(df1)[max.col(df1, "first")]
df1$expectedOutput
#[1] "Version10" "Version9"  "Version8"  "Version1" 

data

df1 <- structure(list(Version10 = c(1L, 0L, 0L, 0L), Version8 = c(1L, 
 0L, 1L, 0L), Version9 = c(0L, 1L, 1L, 0L), Version5 = c(0L, 1L, 
1L, 0L), Version1 = c(0L, 0L, 1L, 1L)), .Names = c("Version10", 
"Version8", "Version9", "Version5", "Version1"), class = "data.frame", 
row.names = c(NA, -4L))

Answer 2

You are missing something in row 3, I guess the expected outcome should be version 9 her instead of v8.

Secondly, as you are defining string data frame so use the quotation around versions. Try something this with correct logic.

df<data.frame(cbind('Version10','Version9','Version8','Version5','Version1'))