在Python中将（单个列表）与（列表列表）进行比较

Question

I am working with python 3.6. I have a list coordinates = [101758584, 101837149, 101844851] and another list of lists rows = [['1', '36933096', 'CSF3R', 'chr1:g.36933096T>C', 'Pathogenic', 'Tarceva\\n'], ['2', '25463483', 'DNMT3A', 'chr2:g.25463483G>A', 'Pathogenic', 'Tarceva\\n'], ['2', '25469502', 'DNMT3A', 'chr2:g.25469502C>T', 'risk factor', 'Iressa\\n']].... and this list goes on . I want to check if the numbers present in coordinates are present in the rows list. So far what I have tried is -

coordinates = [101758584, 101837149, 101844851]
rows = [['1', '36933096', 'CSF3R', 'chr1:g.36933096T>C', 'Pathogenic', 'Tarceva\n'], ['2', '25463483', 'DNMT3A', 'chr2:g.25463483G>A', 'Pathogenic', 'Tarceva\n'], ['2', '25469502', 'DNMT3A', 'chr2:g.25469502C>T', 'risk factor', 'Iressa\n']]
    for e in rows:
            if e[0] in coordinates:
                chromo_final.append(e)

        print(chromo_final)

The output for this is an empty list. The second thing that I tried was -

chromo_final=[x for x in rows if x[0] in coordinates]
print(chromo_final)

Even this code gives an empty list. One example of the output is -

7   101755060   CUX1    chr7:g.101755060A>G Likely pathogenic   Cotellic

The pattern in the coordinates is present on the second position of the output. This output can be of many lines as my list of lists is huge. I would love to know so as to exactly where I am going wrong and also how can I go about this code to get the correct output.

Answer 1

一种简单的方法是使用list comprehension ，要指出的一件事是coordinates和rows[1]数据类型不同，并且您的坐标在index-1因此使用x[1]代替x[0] x[1]

>>> [i for i in rows for j in coordinates if i[1] == str(j)]