C＃正则表达式，用于x个连字符分隔的AZ组数

Question

I am trying to match the following pattern.

A minimum of 3 'groups' of alphanumeric characters separated by a hyphen.

Eg: ABC1-AB-B5-ABC1

Each group can be any number of characters long.

I have tried the following:

^(\w*(-)){3,}?$

This gives me what I want to an extent.

ABC1-AB-B5-0001 fails, and ABC1-AB-B5-0001- passes.

I don't want the trailing hyphen to be a requirement.

I can't figure out how to modify the expression.

Answer 1

Your ^(\\w*(-)){3,}?$ pattern even allows a string like ----- because the only required pattern here is a hyphen: \\w* may match 0 word chars. The - may be both leading and trailing because of that.

You may use

\A\w+(?:-\w+){2,}\z

Details :

• \\A - start of string
• \\w+ - 1+ word chars (that is, letters, digits or _ symbols)
• (?:-\\w+){2,} - 2 or more sequences of:
  • - - a single hyphen
  • \\w+ - 1 or more word chars
• \\z - the very end of string.

See the regex demo .

Or, if you do not want to allow _ :

\A[^\W_]+(?:-[^\W_]+){2,}\z

or to only allow ASCII letters and digits:

\A[A-Za-z0-9]+(?:-[A-Za-z0-9]+){2,}\z

Answer 2

可能是这样的：

^\w+-\w+-\w+(-\w+)*$

Answer 3

^(\w+-){2,}(\w+)-?$

匹配2个以上由连字符分隔的组，然后匹配一个可能由连字符终止的组。

Answer 4

((?:-?\\w+){3,})

Matches minimum 3 groups, optionally starting with a hyphen, thus ignoring the trailing hyphen.

Note that the \\w word character also select the underscore char _ as well as 0-9 and az

link to demo