在某些正则表达式后匹配任何z / AZ和-字符

Question

i need a certain string to be in this format: [0000] anyword

so between the [] brackets i need 4 numbers, followed by a whitespace. after that only characters ranging from a to z and - characters are allowed.

so this should be allowed:

[0000] foo-bar

[0000] foo

[0000] foo-bar-foo

etc..

so far i have this:

\[[0-9]{4}\]\s

this matches the [0000] , so it maches the brackets with 4 numbers in it and the whitespace. i can't seem to find something that allows charachters after that. i've tried putting a single "." at the end of the expression as this should match any character but this doesnt seem to be working.

\[[0-9]{4}\]\s^[A-Z]+[a-zA-Z]*$

the above isn't working either..

i need this expression as a Validationexpression for an asp.net custom validator.

any help will be appreciated

Answer 1

(\\[[0-9]{4}\\])\\s+([Az\\-]+) should hopefully work. It'll capture the numbers and letters into two capture groups as well.

Answer 2

试试这个

@"\[[0-9]{4}\] [a-zA-Z]+(-[a-zA-Z]+)*"

Answer 3

This works for your input: http://regexr.com/?30sb7 . Unlike Cornstalk's answer it does not capture anything, and - can indeed be placed later in a range if it's escaped.