如何在python3中将24位wav文件转换为16或32位文件

Question

I am trying to make spectrogram's of a bunch of .wav files so I can further analyze them(in python 3.6), however, I keep getting this nasty error

 ValueError: Unsupported bit depth: the wav file has 24-bit data.

I have looked into other stack overflow posts such as How do I write a 24-bit WAV file in Python? but theses didn't solve the issue!

I found a audio library called Pysoundfile

http://pysoundfile.readthedocs.io/en/0.9.0/

I installed it with

pip3 install pysoundfile

I have looked over the documentation and it is still not clear to me how to convert a 24-bit .wav file to a 32-bit wav file or a 16-bit wav file so that I can create a spectrogram from it.

Any help would be appreciated!

Answer 1

I would suggest using SoX for this task. Changing the bit depth is very simple:

sox old.wav -b 16 new.wav

If you must use Python, then you could use PySoundFile as you found. Here's a little code snippet:

import soundfile

data, samplerate = soundfile.read('old.wav')
soundfile.write('new.wav', data, samplerate, subtype='PCM_16')

You should also use soundfile.available_subtypes to see which subtypes you can convert a file to. Here's its sample usage, taken from their documentation:

>>> import soundfile as sf
>>> sf.available_subtypes('FLAC')
{'PCM_24': 'Signed 24 bit PCM',
 'PCM_16': 'Signed 16 bit PCM',
 'PCM_S8': 'Signed 8 bit PCM'}

Answer 2

I found the solution with the help of Berk Özbalcı I wrote a function below to convert a directory of .wav files to 16-bit wav files

def convertAllFilesInDirectoryTo16Bit(directory):
    for file in os.listdir(directory):
         if(file.endswith('.wav')):
             nameSolo = file.rsplit('.', 1)[0]
             print(directory + nameSolo )
             data, samplerate = soundfile.read(directory + file)                

           soundfile.write('/Users/yournamehere/Desktop/folderwhereyouwanttosae/' + nameSolo + '16BIT.wav', data, samplerate, subtype='PCM_16')
            print("converting " + file + "to 16 - bit")