MySQL-具有总和的DISTINCT

Question

I have a table with the following columns:

• customerID - customer IDs with multiple rows with same ID
• actionVal - 0 or 1

I want to count how many customers ( customerID ) have more then one row with ( actionVal ) equal to 1

I came up with this SQL statement with no luck...

SELECT customerID, SUM(actionVal), COUNT(DISTINCT customerID) as total_C
FROM table1 
GROUP BY customerID 
HAVING SUM(actionVal) > 1

The result I'm looking for would be ['total_C']

Answer 1

Close, you just need to count the customers from your query:

SELECT COUNT(*) as total_C
FROM (
  SELECT customerID, SUM(actionVal)
  FROM table1 
  GROUP BY customerID 
  HAVING SUM(actionVal) > 1
) as q;

Answer 2

You will have to count the rows returned by your query . Something like this.

SELECT COUNT(1) FROM (
SELECT customerID, SUM(actionVal) as act_sum
FROM table1 
GROUP BY customerID 
HAVING act_sum > 1
) AS tab

I hope this helped.