如何使用调整后的字符串索引使字符串第二次通过循环运行？

Question

Trying to write code that will take an input string and "abbreviate" it. for example if aabb is given then the output should be bc. Basically if there's any double letters it goes up to the next letter in the alphabet so aa = b and so on. This works fine for the first run through but it won't loop through until completion. if the given string is aaaa the output should be c but instead the code outputs bb. how can I adjust my code to run the string an appropriate amount of times?

string abbreviate (string loc){

int loopCount;
sort(loc.begin(), loc.end());

for ( unsigned int i = 0; i < loc.length() ; i++){


    if(loc[i] == loc[i+1]) {
        if(loc[i] == 'a'){
            loc[i] = 'b';
            loc[i+1] = 0;

        }else if(loc[i] == 'b'){
            loc[i] ='c';
            loc[i+1]= 0;
        }else if(loc[i] == 'c'){
            loc[i] ='d';
            loc[i+1]= 0;
        }else if(loc[i] == 'd'){
            loc[i] = 'e';
            loc[i+1]= 0;
        }else if(loc[i] == 'e'){
            loc[i] ='f';
            loc[i+1]= 0;
        }else if(loc[i] == 'f'){
            loc[i] ='g';
            loc[i+1]= 0;
        }else if(loc[i] == 'g'){
            loc[i] ='h';
            loc[i+1]= 0;
        }else if(loc[i] == 'h'){
            loc[i] ='i';
            loc[i+1]= 0;
        }else if(loc[i] == 'i'){
            loc[i] ='j';
            loc[i+1]= 0;
        }else if(loc[i] == 'j'){
            loc[i] ='k';
            loc[i+1]= 0;
        }else if(loc[i] == 'k'){
            loc[i] ='l';
            loc[i+1]= 0;
        }else if(loc[i] == 'l'){
            loc[i] ='m';
            loc[i+1]= 0;
        }else if(loc[i] == 'm'){
            loc[i] ='n';
            loc[i+1]= 0;
        }else if(loc[i] == 'n'){
            loc[i] ='o';
            loc[i+1]= 0;
        }else if(loc[i] == 'o'){
            loc[i] ='p';
            loc[i+1]= 0;
        }else if(loc[i] == 'p'){
            loc[i] ='q';
            loc[i+1]= 0;
        }else if(loc[i] == 'q'){
            loc[i] ='r';
            loc[i+1]= 0;
        }else if(loc[i] == 'r'){
            loc[i] ='s';
            loc[i+1]= 0;
        }else if(loc[i] == 's'){
            loc[i] ='t';
            loc[i+1]= 0;
        }else if(loc[i] == 't'){
            loc[i] ='u';
            loc[i+1]= 0;
        }else if(loc[i] == 'u'){
            loc[i] ='v';
            loc[i+1]= 0;
        }else if(loc[i] == 'w'){
            loc[i] ='x';
            loc[i+1]= 0;
        }else if(loc[i] == 'x'){
            loc[i] ='y';
            loc[i+1]= 0;
        }else if(loc[i] == 'y'){
            loc[i] ='z';
            loc[i+1]= 0;
        }


    }
}

return loc;
}

Answer 1

You can have a nested loop with a variable checking if something has been changed in the last loop iteration. For example, your code would look similar to this:

// Pseudocode
bool changed = true; // This will keep track if previous loop has changed any values
while (changed) {
    changed = false; // Set to false at beginning of loop
    for (size_t i = 0; i < stringLength; ++i) {
        if (/*two same characters in a row*/) {
            // Change character to the next one in the alphabet
            changed = true; // This will indicate the outer loop to run again
        }
    }
}

This way, the program will only stop if all of the concurring characters have been changed.

There are a few other issues in your code such as indexing errors, here is an example how I implemented your functionality: https://wandbox.org/permlink/n0hk8SOpNEo6iZV7