Python中的5x5网格

Question

developers, I want to make a 5x5 grid in python I try this code but I fail to generate my required output here I use abc for while loop

    l1 = []
    abc = 1
    while abc == 5:
       for i in range(1,6,1):
          l1.append(i)
           abc+=1
     print(l1)

but its out was only []

I want this type of output

['0','0','0','0','0']

['0','0','0','0','0']

['0','0','0','0','0']

['0','0','0','0','0']

['0','0','0','0','0']

Answer 1

Your logic is quite confusing since you have a conditional abc == 5 in your while loop, so it will never execute. You can generate what you want by:

[[i for i in range(j, j + 5)] for j in range(0, 25, 5)]

so the output will be:

[[0, 1, 2, 3, 4],
 [5, 6, 7, 8, 9],
 [10, 11, 12, 13, 14],
 [15, 16, 17, 18, 19],
 [20, 21, 22, 23, 24]]

in case you want it to start at 1 and finish at 25:

[[i for i in range(j, j + 5)] for j in range(1, 26, 5)]

so the output will be:

[1, 2, 3, 4, 5],
 [6, 7, 8, 9, 10],
 [11, 12, 13, 14, 15],
 [16, 17, 18, 19, 20],
 [21, 22, 23, 24, 25]]

Update: (based on the output you provided in the question) :

grid = [[i for i in range(j, j + 5)] for j in range(0, 25, 5)]
for item in grid:
    print(item)

Answer 2

Here's my guess as to what I believe you are asking:

>>> l1 = [[i for i in range(1, 6)] for _ in range(5)]
>>> print(*l1, sep='\n')
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
>>> 

This print() idiom is simple enough to memorize and use whenever you're in the Python shell and want to quickly examine a two dimensional list.