[英]5x5 Grid in Python
開發人員,我想在python中制作5x5網格,我嘗試使用此代碼,但在這里我無法生成所需的輸出,我在while循環中使用abc
l1 = []
abc = 1
while abc == 5:
for i in range(1,6,1):
l1.append(i)
abc+=1
print(l1)
但它的出局只是[]
我想要這種類型的輸出
['0','0','0','0','0']
['0','0','0','0','0']
['0','0','0','0','0']
['0','0','0','0','0']
['0','0','0','0','0']
您的邏輯非常混亂,因為您的while循環中有條件abc == 5
,因此它將永遠不會執行。 您可以通過以下方式生成所需的內容:
[[i for i in range(j, j + 5)] for j in range(0, 25, 5)]
所以輸出將是:
[[0, 1, 2, 3, 4],
[5, 6, 7, 8, 9],
[10, 11, 12, 13, 14],
[15, 16, 17, 18, 19],
[20, 21, 22, 23, 24]]
如果您希望它從1開始並在25結束:
[[i for i in range(j, j + 5)] for j in range(1, 26, 5)]
所以輸出將是:
[1, 2, 3, 4, 5],
[6, 7, 8, 9, 10],
[11, 12, 13, 14, 15],
[16, 17, 18, 19, 20],
[21, 22, 23, 24, 25]]
更新:(基於您在問題中提供的輸出) :
grid = [[i for i in range(j, j + 5)] for j in range(0, 25, 5)]
for item in grid:
print(item)
關於我相信您在問的問題,這是我的猜測:
>>> l1 = [[i for i in range(1, 6)] for _ in range(5)]
>>> print(*l1, sep='\n')
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
>>>
這個print()
用法很簡單,足以記住和使用,只要您在Python外殼中並且想要快速檢查一個二維列表。
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