[英]5x5 Grid in Python
开发人员,我想在python中制作5x5网格,我尝试使用此代码,但在这里我无法生成所需的输出,我在while循环中使用abc
l1 = []
abc = 1
while abc == 5:
for i in range(1,6,1):
l1.append(i)
abc+=1
print(l1)
但它的出局只是[]
我想要这种类型的输出
['0','0','0','0','0']
['0','0','0','0','0']
['0','0','0','0','0']
['0','0','0','0','0']
['0','0','0','0','0']
您的逻辑非常混乱,因为您的while循环中有条件abc == 5
,因此它将永远不会执行。 您可以通过以下方式生成所需的内容:
[[i for i in range(j, j + 5)] for j in range(0, 25, 5)]
所以输出将是:
[[0, 1, 2, 3, 4],
[5, 6, 7, 8, 9],
[10, 11, 12, 13, 14],
[15, 16, 17, 18, 19],
[20, 21, 22, 23, 24]]
如果您希望它从1开始并在25结束:
[[i for i in range(j, j + 5)] for j in range(1, 26, 5)]
所以输出将是:
[1, 2, 3, 4, 5],
[6, 7, 8, 9, 10],
[11, 12, 13, 14, 15],
[16, 17, 18, 19, 20],
[21, 22, 23, 24, 25]]
更新:(基于您在问题中提供的输出) :
grid = [[i for i in range(j, j + 5)] for j in range(0, 25, 5)]
for item in grid:
print(item)
关于我相信您在问的问题,这是我的猜测:
>>> l1 = [[i for i in range(1, 6)] for _ in range(5)]
>>> print(*l1, sep='\n')
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
>>>
这个print()
用法很简单,足以记住和使用,只要您在Python外壳中并且想要快速检查一个二维列表。
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