将C ++模板与std :: function和std :: bind一起使用

Question

I am trying to create a template class which would in turn generate a wrapper over a function. The class will then return the wrapper as result. I would like to use template to have general class that will work with any function with different signatures, such as:

1. std::function<void()>task = std::bind(fun1, param1, param2);
2. std::function<int(int, int)>task = std::bind(fun2, param1, param2);

I would like to have something like this:

template <typename T1, typename T2>
class A {
  A (string param1, string param2) {
    // The created wrapper here i.e. 'task' will be returned by the class.
    function<T1>task = bind(T2, param1, param2);
  }

  // Return the created wrapper in the constructor.
  function<T1> returnWrapper() {
    return task;
  }
};

The code above is mostly a pseudo code since it cannot be compiled, but gives an idea about what I am looking for. Is there any solution for this? I think there should be more than simply use a template for a function's signature. Any help would be highly appreciated. I also would like to be able to pass arbitrary number of parameters to 'bind' if possible.

Answer 1

I think I solved the problem! I had to define a class which takes two type names inside a template and pass one of them to std::function as function signature after currying and use the second one in the constructor to define the curried function (result function after wrapping) in std::bind. Then everything worked fine! There might be some better solution, but this was the best and more or less clear solution I got. Here is the got snippet of the solution I found! Hope it helps the other with the same issue:

#include <iostream>
#include <functional>

using namespace std;

class A {
  private:
    template <typename T1, typename T2>
    class B { 
      private:
        function<T1>ff;

      public:
        B(T2 fun) {
          ff = bind(fun, 1, placeholders::_1);
        }

        virtual ~B() {
        }

        int exec(int x) {
          return ff(x);
        }
    };

    static int myFun(int x, int y) {
      return x + y;
    }

  public:
    A() { 
    };

    int test() {
      B<int(int), int (*)(int, int)> b(&myFun);
      return b.exec(10);
    }

    virtual ~A() {
    };
};

int main() {
  A a;

  // Correct result is '11' since we pass 11 and 1 is in the curried function.
  cout << "test result: " << a.test() << endl;

  return 0;
}