[英]Iterable Unpacking Evaluation Order
I recently answered a question where a user was having trouble because they were appending a multi-dimensional array to another array, and it was brought to my attention in my answer that it is possible to use iterable unpacking to populate an x
and y
value and assign to board[x][y]
on the same line. 我最近回答了一个用户因将多维数组附加到另一个数组而遇到麻烦的问题 ,在我的回答中引起了我的注意,可以使用迭代拆包来填充x
和y
值,并且在同一行上分配给board[x][y]
。
I had expected this to throw an error as x
and y
had at the time not been defined, as, even in the iterable-unpacking
tag it reads: 我曾预计这会引发错误,因为x
和y
当时尚未定义,即使在读取的iterable-unpacking
标签中也是如此:
elements of an iterable are simultaneously assigned to multiple values 可迭代的元素同时分配给多个值
This can be seen as working in the following example: 在以下示例中,这可以看作是有效的:
>>> board = [[0, 0], [0, 0]]
>>> move = [0, 1, 2]
>>> x, y, board[x][y] = move
>>> board
[[0, 2], [0, 0]]
Which is the same as: 与以下内容相同:
>>> board = [[0, 0], [0, 0]]
>>> move = [0, 1, 2]
>>> x = move[0]
>>> y = move[1]
>>> board[x][y] = move[2]
>>> board
[[0, 2], [0, 0]]
And yet when calculating the Fibonacci sequence using: 但是,当使用以下方法计算斐波那契数列时:
a, b = b, a + b
It doesn't evaluate as: 它的评估结果不为:
a = b
b = a + b
And when swapping values with: 并与以下值交换时:
a, b = b, a
It doesn't evaluate as: 它的评估结果不为:
a = b
b = a
So why does this work in the first example? 那么,为什么在第一个示例中这样做呢?
The right side of the =
is always evaluated first, in this case it is packing a tuple. 总是首先评估=
的右侧,在这种情况下,它正在包装一个元组。 That tuple is then unpacked when interpreting the left hand side. 然后,在解释左侧时会打开该元组的包装。 The left and right sides do not share knowledge of variables. 左侧和右侧不共享变量知识。 The RHS becomes a value and then the LHS uses that value to assign to the variables (labels). RHS成为一个值,然后LHS使用该值将其分配给变量(标签)。
In your example the values of x
and y
are determined after the RHS is evaluated. 在您的示例中,在评估RHS之后确定x
和y
的值。 The unpacking then occurs left to right, so that board[x][y]
has valid indices. 然后解压缩从左到右发生,因此board[x][y]
具有有效的索引。
Switching the order demonstrates the unpacking sequence: 切换顺序说明了拆箱顺序:
>>> board[x][y], x, y = move[2], move[0], move[1]
---------------------------------------------------------------------------
NameError Traceback (most recent call last)
<ipython-input-7-a984ef3168f8> in <module>()
----> 1 board[x][y], x, y = move[2], move[0], move[1]
NameError: name 'x' is not defined
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