如何在SQL Server中按列按max（date）组获取数据

Question

In the table below I need lastservice data based on the last date group by nopol.

Table data:

I tried to use the query below

SELECT 
    TGL, A.NOPOL, LASTSERVICE 
FROM 
    TRREALPRWT AS A
INNER JOIN 
    (SELECT 
         MAX(TGLREAL) AS TGL, NOPOL 
     FROM 
         TRREALPRWT 
     GROUP BY 
         NOPOL) AS B ON B.NOPOL = A.NOPOL
GROUP BY 
    A.NOPOL, TGL,LASTSERVICE

but the results obtained are not per nopol.

What I should do from the query so that it produces data like the following

| NOPOL   | LASTSERVICE | TGLREAL                   |
| L9235VB | 224270      | 2018-01-26 00: 00: 00.000 |
| B9891JT | 219270      | 2018-02-28 00: 00: 00.000 |

Answer 1

I believe this should work, assuming TGLREAL is your date.

SELECT TGL,A.NOPOL,LASTSERVICE FROM TRREALPRWT
WHERE TGLREAL IN (SELECT MAX(TGLREAL) FROM  TRREALPRWT)

Answer 2

Is seems to be use only group by clause no need to inner query

select nopol, min(LASTSERVICE) LASTSERVICE, max(TGL) TGLREAL  
from TRREALPRWT 
group by nopol

Answer 3

Take all MAX(TGL) for all NOPOL in an inner query and join it again with your original table matching on NOPOL and MAX(TGL) values.

SELECT T.NOPOL, T.TGL, T.LASTSERVICE
FROM
YOUR_TABLE T
INNER JOIN
(SELECT NOPOL, MAX(TGL) AS MAX_TGL FROM YOUR_TABLE GROUP BY NOPOL) A
ON T.NOPOL = A.NOPOL AND T.TGL = A.MAX_TGL;

Answer 4

The sample output in the question seems to indicate that you want the first tgl for each nopol, max(lastservice)

SELECT nopol,MIN(lastservice) lastservice,  MAX(tgl) tglreal
FROM trreal
GROUP BY nopol