[英]Swift equivalent of my Objective-C block
I can't seem to figure out how to call an Objective-C block from Swift!我似乎无法弄清楚如何从 Swift 调用 Objective-C 块!
I have the following Objective-C method:我有以下 Objective-C 方法:
- (void)myMethod:(NSDictionary *)selection success:(MyBlock)success;
Where MyBlock is: MyBlock在哪里:
typedef void(^MyBlock)(BOOL success, NSDictionary* options);
It either complains it can't cast:它要么抱怨它无法投射:
"Cannot convert value of type '(Bool, Dictionary<AnyHashable, Any>) -> ()' to expected argument type 'MyBlock!' (aka 'ImplicitlyUnwrappedOptional<(Bool, Optional<Dictionary<AnyHashable, Any>>) -> ()>')"
or I'm getting a SIGABRT when I try to call the method from Swift using any of the following:或者当我尝试使用以下任一方法从 Swift 调用该方法时收到 SIGABRT:
myInstance.myMethod(myOptions) { (success, options) in
...
}
myInstance.myMethod(myOptions) { (success: Bool, options: Dictionary<AnyHashable, Any>?) in
...
}
myInstance.myMethod(myOptions) { (success: Bool!, options: [AnyHashable: Any]?) in
...
}
myInstance.myMethod(myOptions, success: { (success, options) in
...
})
myInstance.myMethod(myOptions, success: { (success, options) in
...
} as MyBlock)
myInstance.myMethod(myOptions, success: { (success: Bool, options: Dictionary<AnyHashable, Any>?) in
...
})
myInstance.myMethod(myOptions, success: { (success: Bool!, options: Dictionary<AnyHashable, Any>?) in
...
})
myInstance.myMethod(myOptions, success: { (success: Bool!, options: Dictionary<AnyHashable, Any>?) in
...
} as MyBlock)
myInstance.myMethod(myOptions, success: { (success: Bool!, options: [AnyHashable: Any]?) in
...
})
myInstance.myMethod(myOptions, success: { (success: Bool, options: [AnyHashable: Any]?) in
...
})
What do I do?我该怎么办?
The equivalent swift code of your MyBlock :您的MyBlock的等效 swift 代码:
typedef void(^MyBlock)(BOOL success, NSDictionary* options)
- (void)myMethod:(NSDictionary *)selection success:(MyBlock)success;
is as follows:如下:
public typealias MyBlock = (Bool, [String : Any]) -> (Void)
func myMethod(selection: [String : Any], success: MyBlock)
so when you use myMethod for example:所以当你使用myMethod例如时:
self.myMethod(selection: yourDictionary) { (success, options) -> (Void) in
//handle here
}
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