[英]Swift equivalent of my Objective-C block
我似乎無法弄清楚如何從 Swift 調用 Objective-C 塊!
我有以下 Objective-C 方法:
- (void)myMethod:(NSDictionary *)selection success:(MyBlock)success;
MyBlock在哪里:
typedef void(^MyBlock)(BOOL success, NSDictionary* options);
它要么抱怨它無法投射:
"Cannot convert value of type '(Bool, Dictionary<AnyHashable, Any>) -> ()' to expected argument type 'MyBlock!' (aka 'ImplicitlyUnwrappedOptional<(Bool, Optional<Dictionary<AnyHashable, Any>>) -> ()>')"
或者當我嘗試使用以下任一方法從 Swift 調用該方法時收到 SIGABRT:
myInstance.myMethod(myOptions) { (success, options) in
...
}
myInstance.myMethod(myOptions) { (success: Bool, options: Dictionary<AnyHashable, Any>?) in
...
}
myInstance.myMethod(myOptions) { (success: Bool!, options: [AnyHashable: Any]?) in
...
}
myInstance.myMethod(myOptions, success: { (success, options) in
...
})
myInstance.myMethod(myOptions, success: { (success, options) in
...
} as MyBlock)
myInstance.myMethod(myOptions, success: { (success: Bool, options: Dictionary<AnyHashable, Any>?) in
...
})
myInstance.myMethod(myOptions, success: { (success: Bool!, options: Dictionary<AnyHashable, Any>?) in
...
})
myInstance.myMethod(myOptions, success: { (success: Bool!, options: Dictionary<AnyHashable, Any>?) in
...
} as MyBlock)
myInstance.myMethod(myOptions, success: { (success: Bool!, options: [AnyHashable: Any]?) in
...
})
myInstance.myMethod(myOptions, success: { (success: Bool, options: [AnyHashable: Any]?) in
...
})
我該怎么辦?
您的MyBlock的等效 swift 代碼:
typedef void(^MyBlock)(BOOL success, NSDictionary* options)
- (void)myMethod:(NSDictionary *)selection success:(MyBlock)success;
如下:
public typealias MyBlock = (Bool, [String : Any]) -> (Void)
func myMethod(selection: [String : Any], success: MyBlock)
所以當你使用myMethod例如時:
self.myMethod(selection: yourDictionary) { (success, options) -> (Void) in
//handle here
}
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