Swift 相当于我的 Objective-C 块

Question

我似乎无法弄清楚如何从 Swift 调用 Objective-C 块！

我有以下 Objective-C 方法：

- (void)myMethod:(NSDictionary *)selection success:(MyBlock)success;

MyBlock在哪里：

typedef void(^MyBlock)(BOOL success, NSDictionary* options);

它要么抱怨它无法投射：

"Cannot convert value of type '(Bool, Dictionary<AnyHashable, Any>) -> ()' to expected argument type 'MyBlock!' (aka 'ImplicitlyUnwrappedOptional<(Bool, Optional<Dictionary<AnyHashable, Any>>) -> ()>')"

或者当我尝试使用以下任一方法从 Swift 调用该方法时收到 SIGABRT：

myInstance.myMethod(myOptions) { (success, options) in
    ...
}

myInstance.myMethod(myOptions) { (success: Bool, options: Dictionary<AnyHashable, Any>?) in
    ...
}

myInstance.myMethod(myOptions) { (success: Bool!, options: [AnyHashable: Any]?) in
    ...
}

myInstance.myMethod(myOptions, success: { (success, options) in
    ...
})

myInstance.myMethod(myOptions, success: { (success, options) in
    ...
} as MyBlock)

myInstance.myMethod(myOptions, success: { (success: Bool, options: Dictionary<AnyHashable, Any>?) in
    ...
})

myInstance.myMethod(myOptions, success: { (success: Bool!, options: Dictionary<AnyHashable, Any>?) in
    ...
})

myInstance.myMethod(myOptions, success: { (success: Bool!, options: Dictionary<AnyHashable, Any>?) in
        ...
} as MyBlock)

myInstance.myMethod(myOptions, success: { (success: Bool!, options: [AnyHashable: Any]?) in
    ...
})

myInstance.myMethod(myOptions, success: { (success: Bool, options: [AnyHashable: Any]?) in
    ...
})

我该怎么办？

Answer 1

您的MyBlock的等效 swift 代码：

typedef void(^MyBlock)(BOOL success, NSDictionary* options)

- (void)myMethod:(NSDictionary *)selection success:(MyBlock)success;

如下：

public typealias MyBlock = (Bool, [String : Any]) -> (Void)

func myMethod(selection: [String : Any], success: MyBlock)

所以当你使用myMethod例如时：

self.myMethod(selection: yourDictionary) { (success, options) -> (Void) in
     //handle here
}