如何使用不可变的js取消列表中的每个元素？

Question

I want to unshift each element of an array in immutable list

My execution resulted in the following. enter image description here

-> List[List[new_element], element, element, element]

I want this result.

-> List[new_element, element, element, element]

How can i fix it?

---

case types.MEMO_LIST_SUCCESS:

    if (action.listType === 'new') {        
        if(action.data.length !== 0) {
            return state.setIn(['memoList', 'status'], 'SUCCESS')
                                .setIn(['memoList', 'data'], data.unshift(fromJS(action.data)));
        } else {
            return state.setIn(['memoList', 'status'], 'SUCCESS')
        }
    }

Answer 1

From the expression action.data.length in your code example it looks like you should iterate action.data and add each item to data .

If action.data is an array or other iterable, fromJS(action.data) will return you a new List .

---

You could use Array.prototype.reduce and pass data as initial value for the accumulation, adding to it by iterating action.data :

if (action.listType === 'new') {
    const newData = action.data.reduce((acc, item) => acc.unshift(fromJs(item)), data);
    return state
        .setIn(['memoList', 'status'], 'SUCCESS')
        .setIn(['memoList', 'data'], newData);
}

Or even easier, use the List::concat method.

Note that the above example reverses the order of items in of action.data , whereas the following example does not.

Also the example above does convert each item to immutable List or Map if it is an array resp. object, whereas the following example does not.

if (action.listType === 'new') {
    return state
        .setIn(['memoList', 'status'], 'SUCCESS')
        .setIn(['memoList', 'data'], fromJS(action.data).concat(data));
}