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Python 中列表理解的错误处理

[英]Error handling for list comprehension in Python

Is there a way to handle errors in a python list comprehension.有没有办法处理 python 列表理解中的错误。 Preferably I would have something like this where the last two values are represented by None :最好我有这样的东西,其中最后两个值由None表示:

values = [try i ["row"] except KeyError None for i in [{"row" : 1}, {"Row" : 0}, {}]]

This throws a syntax error and the only way I can do it is:这会引发语法错误,我能做到的唯一方法是:

values = []
for i in [{"row" : 1}, {"Row" : 0}, {}]:
    try: values.append (i ["row"])
    except KeyError: values.append (None)

I hope there is a more 'neat' way of doing this because the current solution is not preferable due to having to append to a blank list when a list comprehension does this in such a nice way!我希望有一种更“整洁”的方法来做到这一点,因为当列表理解以如此好的方式执行此操作时,由于必须附加到空白列表,因此当前的解决方案并不可取!

you cannot catch an exception from a list comprehension ( How can I handle exceptions in a list comprehension in Python? ).您无法从列表理解中捕获异常( How can I handle exceptions in a list comprehension in Python? )。 But given what you want to do you could use get :但是考虑到您想做什么,您可以使用get

values = [i.get("row") for i in [{"row" : 1}, {"Row" : 0}, {}]]

if the key isn't found in the dictionary get returns None , exactly what you're looking for (it can return anything you want, just by passing the default value as second argument, see Why dict.get(key) instead of dict[key]? )如果在字典中找不到键get返回None ,正是你要找的东西(它可以返回你想要的任何东西,只需将默认值作为第二个参数传递,请参阅为什么 dict.get(key) 而不是 dict [关键]?

You can also check if key is dictionary in list comprehension and return None if it is not present:您还可以检查 key 是否是列表理解中的dictionary ,如果不存在则返回None

key = 'row'
values = [i[key] if key in i else None for i in [{"row" : 1}, {"Row" : 0}, {}]]

You can't handle exceptions directly in a list comprehension, because try is a statement, not an expression.您不能直接在列表理解中处理异常,因为try是一个语句,而不是一个表达式。

However, you can abstract the try out into a separate function:但是,您可以将try抽象为一个单独的函数:

def tryirow(i):
    try: return i["row"]
    except KeyError: return None

values = [tryirow(i) for i in [{"row" : 1}, {"Row" : 0}, {}]]

Of course in this case, as Jean-François Fabre's answer implies, you've just reimplemented the built-in dict.get method:当然,在这种情况下,正如Jean-François Fabre 的回答所暗示的那样,您刚刚重新实现了内置的dict.get方法:

values = [i.get("row") for i in [{"row" : 1}, {"Row" : 0}, {}]]

But this shows how you can solve similar problems more generally: if there's a function that does what you want, call it;但这显示了如何更普遍地解决类似问题:如果有一个函数可以满足您的需求,请调用它; if not, write it.如果没有,写下来。


And of course sometimes, "write out a for statement" is actually the right answer.当然有时候,“写出一个for语句”实际上是正确的答案。 Not everything should be written as a list comprehension, even many things that can .不是所有的东西都应该写成列表理解,即使是很多可以的东西。 I don't think that's relevant here, but it's worth keeping in mind.我认为这在这里无关紧要,但值得牢记。


There was actually a proposal to add a try expression just like the one you're trying to write, PEP 463 .实际上有人提议添加一个try表达式,就像您尝试编写的PEP 463一样。 Why was it rejected?为什么被拒绝了? Because almost all of the use-cases were "get-with-default-fallback" cases where the function you want already exists (like dict.get ) or should exist.因为几乎所有用例都是“get-with-default-fallback”情况,其中您想要的功能已经存在(如dict.get )或应该存在。 Nobody could come up with a common use case that wasn't better written with a separate function or an expanded-out for statement.没有人能想出一个用单独的函数或扩展的for语句编写得更好的常见用例。

In a brand new language, I think it would make more sense to have a try expression and not have methods like dict.get , but in a language that already had dict.get for over a decade before anyone suggested a try expression (and almost two decades before anyone put together a concrete proposal), that would be a bad change to make.在一种全新的语言中,我认为有一个try表达式而不是像dict.get这样的方法更有意义,但是在一种已经有dict.get十多年的语言中,在任何人建议一个try表达式之前(几乎在任何人提出具体建议之前二十年),这将是一个糟糕的改变。

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