[英]Remove characters from specific point until before space using sed or awk
I would like to remove characters from a specific point until just before the first whitespace (without removing the whitespace itself). 我想从特定的点删除字符,直到第一个空格之前(不删除空格本身)。 For instance, my file.txt is as follows: -
例如,我的file.txt如下:-
>DN256845_c2_g1_i1 len=56274 ACGGAGG
>DN256532_c0_g2_i19 len=23973 AATACTC
>DN256979_c8_g3_i32 len=16728 CGAAACT
'X' are numbers such as 1 or 19 or 32 and I would like it to be: - “ X”是数字,例如1或19或32,我希望它是:-
>DN256845_c2_g1 len=56274 ACGGAGG
>DN256532_c0_g2 len=23973 AATACTC
>DN256979_c8_g3 len=16728 CGAAACT
I had used sed 's/_i.*//'
but it removed everything after _i
. 我曾经使用
sed 's/_i.*//'
但是它删除了_i
之后的所有内容。 Other codes that I had tried were sed 's/_i.*\\./\\ /g'
, sed -E 's/_i.*+[^[: :]]//g'
which ended-up with nothing changed. 我尝试过的其他代码是
sed 's/_i.*\\./\\ /g'
, sed -E 's/_i.*+[^[: :]]//g'
最终没有改变。
How do I solve this using sed/awk or any other approach? 如何使用sed / awk或任何其他方法解决此问题? I appreciate the help.
感谢您的帮助。 Thanks!
谢谢!
EDIT: As suggested by Sundeep, I edited the problems for ease of understanding. 编辑:根据Sundeep的建议,我对问题进行了编辑以便于理解。 This data are actually Trinity transcripts identifier.
此数据实际上是Trinity成绩单标识符。 I need to remove the identifier (_i1 and so on) for some analysis).
我需要删除标识符(_i1等)以进行一些分析)。
In awk: 在awk中:
$ awk '{sub(/_[^_ ]+ /," ")}1' file
>DN256845_c2_gXX len=56274 ACGGAGG
>DN256532_c0_gXX len=23973 AATACTC
>DN256979_c8_gXX len=16728 CGAAACT
Same with sed
: 与
sed
相同:
$ sed 's/_[^_ ]\+ / /' file
Replace the first instance of an underscore, everything but an underscore or a space and a space with a space. 替换下划线的第一个实例,除下划线或空格和带空格的空格外的所有内容。
Edit: I wonder why I didn't post this obvious awk manipulating the end of $1: 编辑:我想知道为什么我没有发布这个明显的awk操纵$ 1的结尾:
$ awk '{sub(/_[^_]+$/,"",$1)}1' file
'X' are numbers such as 1 or 19 or 32
“ X”是数字,例如1或19或32
It is a good idea to give sample as close as possible to real use case. 尽可能使样本接近实际用例是一个好主意。 I've changed sample data to change
X
after i
to numbers.. if this doesn't help, please add better sample to question 我更改了样本数据,将
i
更改为数字X
如果这没有帮助,请向问题中添加更好的样本
$ cat ip.txt
>DN256845_c2_gXX_i1 len=56274 ACGGAGG
>DN256532_c0_gXX_i19 len=23973 AATACTC
>DN256979_c8_gXX_i32 len=16728 CGAAACT
$ sed 's/_i[0-9]* / /' ip.txt
>DN256845_c2_gXX len=56274 ACGGAGG
>DN256532_c0_gXX len=23973 AATACTC
>DN256979_c8_gXX len=16728 CGAAACT
_i[0-9]*
match _
followed by zero or more numbers followed by space _i[0-9]*
匹配_
后跟零个或多个数字,后跟空格 For this use case, this could also be shortened to 对于此用例,也可以缩短为
sed 's/_i[^ ]*//' ip.txt
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