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在文本字符串中查找整数/浮点数/字符串并放入数组

[英]Find integers/floats/strings in a string of text and put in array

I have a string and want split them in an array based on type. 我有一个字符串,想根据类型将它们拆分为一个数组。 I can extract numbers and floats like below, but is not complete to my goal 我可以像下面那样提取数字和浮点数,但是并没有达到我的目标

 var arr = "this is a string 5.86 x10‘9/l 1.90 7.00"
   .match(/\d+\.\d+|\d+\b|\d+(?=\w)/g)
   .map(function (v) {return v;});

 console.log(arr);

 arr = [5.86, 10, 9, 1.9, 7]

I would like have even chunk of string type and mixed like "x10'9/l": 我什至希望有字符串类型的大块并且像“ x10'9 / l”那样混合:

 arr = ["this is a string", 5.86, "x10‘9/l", 1.9, 7]

can someone figure out? 有人可以找出来吗?

 const result = [];

 const str = "this is a string 5.86 x10‘9/l 1.90 7.00";

 result.push(str.split(" ").reduce((acc, part) => isNaN(part) ? acc + " " + part : ((acc && result.push(acc)), result.push(+part), ""), ""));

I came up with this: 我想出了这个:

 var arr = [];
 var str = "this is a string 5.86 x10‘9/l 1.90 7.00";
 arr.push(str.split(" ").reduce((acc, part) => isNaN(part) ? acc + " " + part : (arr.push(acc.trim(), +part), ""), ""));

 var result = arr,
     len = arr.length, i;

 for(i = 0; i < len; i++ ) {
     result[i] && result.push(result[i]);  // copy non-empty values to the end of the array
 }

 result.splice(0 , len);  // cut the array and leave only the non-empty values
 console.log(result); 

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