[英]byte literal array to string
I am new to Python, I am calling an external service and printing the data which is basically byte literal array. 我是Python的新手,我在调用外部服务并打印基本上是字节文字数组的数据。
results = q.sync('([] string 2#.z.d; `a`b)')
print(results)
[(b'2018.06.15', b'a') (b'2018.06.15', b'b')]
To Display it without the b
, I am looping through the elements and decoding the elements but it messes up the whole structure. 为了不使用
b
显示它,我正在遍历元素并解码元素,但是它弄乱了整个结构。
for x in results:
for y in x:
print(y.decode())
2018.06.15
a
2018.06.15
b
Is there a way to covert the full byte literal array to string array (either of the following) or do I need to write a concatenate function to stitch it back? 有没有一种方法可以将全字节文本数组转换为字符串数组(以下两种方法之一),或者我需要编写一个连接函数来将其缝合起来?
('2018.06.15', 'a') ('2018.06.15', 'b')
(2018.06.15,a) (2018.06.15,b)
something like the following (though I want to avoid this approach ) 类似于以下内容(尽管我想避免这种方法)
for x in results:
s=""
for y in x:
s+="," +y.decode()
print(s)
,2018.06.15,a
,2018.06.15,b
Following the previous answer, your command should be as follows: This code will result in a list of tuples. 按照上一个答案,您的命令应如下所示:此代码将生成一个元组列表。
[tuple(x.decode() for x in item) for item in result]
The following code will return tuples: 以下代码将返回元组:
for item in result:
t = ()
for x in item:
t = t + (x.decode(),)
print(t)
您可以在一行中完成此操作,从而返回已解码的元组列表。
[tuple(i.decode() for i in y) for x in result for y in x]
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.