Python 字符串与字节数组到字节数组

Question

ciphertext = base64.b64decode(xxxxxx) //output is b'148,240,50,66,81,26,240,2,101,31'
bytearray(ciphertext) // output is bytearray(b'148,240,50,66,81,26,240,2,101,31')

What am looking for is output of bytearray([148,240,50,66,81,26,240,2,101,31])

Full code:

ciphertext = base64.b64decode("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")

Answer 1

Replace:

bytearray(ciphertext)

with:

bytearray(map(int, ciphertext.split(b',')))
# Or if you prefer genexprs:
bytearray(int(x) for x in ciphertext.split(b','))

The former is just converting the raw bytes to an equivalent bytearray , the latter splits it up by commas and parses the components as int s.