（Python 3）花了一个小时，但找不到错误

Question

I am a beginner at learning python 3 and I am just writing basic programs. I wrote this simple program which would take a number in and divide it by numbers starting from 1 to the square root of the number and find the remainders and add it to a list and print it.

import math

def prime_checker(num):
    n=1
    list_of_remainder=[]
    while n == math.floor(num**0.5):
        var=int(num % n)
        list_of_remainder.append(var)
        n += 1
    return list_of_remainder

var=prime_checker(10)
print(var)

Please tell me what I did wrong. I would like to point out here that I did try to research a bit and find error but I couldn't and only then have I posted this question. The problem that I faced was that it printed out an empty list.

Answer 1

to start with, your while loop is not executed even once. The condition for your while loop is while n == math.floor(num**0.5): The argument num you are passing to the function prime_checker is equal to 10. In this case your condition test is: while 1 == math.floor(10**0.5) which is while 1 == 3 which is obviously not true and as a result the loop is not executed even once.

Answer 2

import math

def prime_checker(num):
    list_of_remainder = []
    number=num;
    n=1
    x=math.floor(number**0.5)

    while n <= x:

        v=int(number % n)

        list_of_remainder.append(v)
        n += 1

    return list_of_remainder

var=prime_checker(10)
print(var)