为什么由cygwin运行时shell中的字符串比较不起作用

Question

I have a very simple script to check the status code returned by a website. I have curl for windows installed from https://curl.haxx.se/download.html . When I run this shell script using git bash it works.

checkServer.sh:

code=`curl -I -sL -w "%{http_code}\\n" "www.google.com" -o /dev/null`

echo "Found code $code"
echo "Found endUrl $endUrl"

echo "x$code"
echo "x200"

if [ "x$code" = "x200" ]; then
    echo "got a 200"
fi

echo "done"

output:

$ sh "C:\Scripts\checkServer.sh"
Found code 200
Found endUrl
x200
x200
done

Why isn't this working? Is there some hidden character in the string returned by curl specifically when it's run in cygwin? I'm already doing a find replace on the script with \\r\\n --> \\n so I don't believe it's line endings but who knows.

Answer 1

user1934428's comment showed me how to find the hidden character returned in curl's httpcode.

using printf %s "$code" | od -cx printf %s "$code" | od -cx in the script to output code with any hidden characters I could see:

Found code 200
Found endUrl
x200
0000000   2   0   0  \r
           3032    0d30
0000004
x200
done

So there's a \\r at the end of it. This came from the \\\\n in the curl command which I'm not even sure why I had in the first place. Removing that fixed it.