[英]Running a Python script in Jupyter Notebook, with arguments passing
I have this simple Python script which I run from my Jupyter Notebook.我有一个从 Jupyter Notebook 运行的简单 Python 脚本。 However the arguments I pass to it seemingly are ignored and this results in an exception:
然而,我传递给它的参数似乎被忽略了,这导致了一个异常:
two_digits.py两位数.py
import sys
input = sys.stdin.read()
tokens = input.split()
a = int(tokens[0])
b = int(tokens[1])
print(a + b)
%run two_digits 3 5
ndexError Traceback (most recent call last)
D:\Mint_ns\two_digits.py in <module>()
5 tokens = input.split()
6
----> 7 a = int(tokens[0])
8
9 b = int(tokens[1])
IndexError: list index out of range
You need to use sys.argv
instead of sys.stdin.read()
:您需要使用
sys.argv
而不是sys.stdin.read()
:
two_digits.py两位数.py
import sys
args = sys.argv # a list of the arguments provided (str)
print("running two_digits.py", args)
a, b = int(args[1]), int(args[2])
print(a, b, a + b)
command line / jupyter magic line:命令行 / jupyter 魔术线:
%run two_digits 3 5
or, with a slightly different output:或者,输出略有不同:
Note: this uses a !
注意:这使用了一个
!
prefix to indicate command line to jupyter前缀以指示 jupyter 的命令行
!ipython two_digits.py 2 3
output: (using magic line %run)输出:(使用魔术线 %run)
running two_digits.py ['two_digits.py', '2', '3']
2 3 5
%%file calc.py
from sys import argv
script, a, b, sign = argv
if sign == '+':
print(int(a) + int(b))
elif sign == '-':
print(int(a) - int(b))
else:
print('I can only add and subtract')
We have several options:我们有几个选择:
%%!
python calc.py 7 3 +
or或者
%run calc.py 7 3 +
or或者
!python calc.py 7 3 +
or with the path in output或输出中的路径
!ipython calc.py 7 3 +
To access the output use the first way with %%!
要访问输出,请使用
%%!
. . Output is a list (IPython.utils.text.SList)
输出是一个列表 (IPython.utils.text.SList)
[In 1]
%%!
python calc.py 7 3 +
[Out 1]
['10']
Now you can use underscore '_'现在您可以使用下划线“_”
[In 2]
int(_[0])/2 # 10 / 2
[Out 2]
5.0
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