C ++如何解释函数参数long（* pPointer）（OtherClass * const，long）？

Question

I can't make any sense of this syntax. What should be passed to the function? A pointer of type long, or a pointer to an instance of OtherClass ? What is the meaning of ,long in the end?

In the doxygen documentation this syntax resolves to:

long(*)(OtherClass *const, long)    pPointer,

I've tried to search for examples of this syntax, but it is difficult to search for braces and asterisks.

Answer 1

It is a pointer to a function that takes an argument of othertype and long and returns a long. The name of the function pointer is pPointer.

Answer 2

This is a pointer to a function named pPointer (the naming is debatable here). Imagine this function somewhere in your code base:

long someFunction(OtherClass *const param1, long param2);

It can be passed to as the type in your question title as

passFct(someFunction);

where the receiving function might look like

void passFct(long (*pPointer) (OtherClass *const, long))
{
    /* ... */

    /* Actually call the function to with pPointer points: */
    pPointer(&otherClassInstance, 10l);
}