I can't make any sense of this syntax. What should be passed to the function? A pointer of type long, or a pointer to an instance of OtherClass
? What is the meaning of ,long
in the end?
In the doxygen documentation this syntax resolves to:
long(*)(OtherClass *const, long) pPointer,
I've tried to search for examples of this syntax, but it is difficult to search for braces and asterisks.
It is a pointer to a function that takes an argument of othertype and long and returns a long. The name of the function pointer is pPointer.
This is a pointer to a function named pPointer
(the naming is debatable here). Imagine this function somewhere in your code base:
long someFunction(OtherClass *const param1, long param2);
It can be passed to as the type in your question title as
passFct(someFunction);
where the receiving function might look like
void passFct(long (*pPointer) (OtherClass *const, long))
{
/* ... */
/* Actually call the function to with pPointer points: */
pPointer(&otherClassInstance, 10l);
}
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