不匹配正则表达式中的一定数量的字符

Question

I have the following expression

diff_pr_EUR-44_cordex_rcp45_mon_ave_2048-2060_minus_2005-2017_mon10_ave1_withsd.nc

I would like to use regex to extract and generate the following string

rcp45_mon10

I have tried this so far with the online regex tester

rcp\d\d[^.]+mon\d+

Which extracts more than what I need...

rcp45_mon_ave_2048-2060_minus_2005-2017_mon10

How can I get regex to skip subsequent characters until it reaches the mon10 part?

Thanks

Answer 1

You can match using two matching groups, and join :

>>> ''.join(re.findall(r'(rcp\d{2}).*?(\_mon\d{2})', s)[0])
'rcp45_mon10'

Answer 2

You may use re.sub here:

>>> s = 'diff_pr_EUR-44_cordex_rcp45_mon_ave_2048-2060_minus_2005-2017_mon10_ave1_withsd.nc'
>>> print (re.sub(r'^.*?(rcp\d+).*(_mon\d+).*', r'\1\2', s))
rcp45_mon10

RegEx Demo

Details:

• ^.*? : Match 0 or of any characters at the start (lazy)
• (rcp\\d+) : Match and capture rcp followed by 1+ digits in group #1
• .* : Match 0 or of any characters (greedy)
• (_mon\\d+) : Match and capture _mon followed by 1+ digits in group #2

• .* : Match anything till the end

• r'\\1\\2' : Replace string by back-references of group #1 and group #2