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计算移动平均线

[英]Calculating a moving average

I struggle to implement the moving average formula in my function. 我很难在我的函数中实现移动平均公式。 Took me quite a while to get where the code is right now. 花了我很长时间才得到代码现在的位置。

Is there a library I could probably take? 我可以带一个图书馆吗?

Input: 输入:

ma([2,3,4,3,2,6,9,3,2,1], 4)

Expected Output: 预期产出:

[None, None, None, 3.0, 3.0, 3.75, 5.0, 5.0, 5.0, 3.75]

My Output: 我的输出:

[None, None, 0.0, 3.0, 3.75, 5.0, 5.0, None, None, None]

I am running into the problem that the middle parts of my result is right but the rest is a mystery. 我遇到的问题是我的结果的中间部分是正确的,但其余部分是个谜。

  1. Why does it return None for the last three values in the list? 为什么列表中的最后三个值都返回None?

def ma(prices, n): def ma(价格,n):

ma = [] sums = [] s = 0 ave = 0

for idx, i in enumerate(prices):
    s += i
    sums.append(s)
    print('idx: ' + str(idx))
    print('list of sums ' + str(sums))
    #print('sum ' + str(s))

if i >= n+1:
    print('sums[idx] ' + str(sums[idx]))
    print('sums[idx-n] ' + str(sums[idx-n]))
    ave = (sums[idx] - sums[idx-n]) / n
    print('ave ' + str(ave))
    ma.append(ave)
    print('ma ' + str(ma))
else:
    m = None
    ma.append(m)
    print('ma ' + str(ma))

(Sorry for all those print function calls, but I really wanted to get to the source of the issue). (对不起,所有这些print函数调用,但我真的想找到问题的根源)。

There were several other logical errors in your code. 您的代码中还有其他几个逻辑错误。 I tried to correct it to make it work as you want. 我试图纠正它,使它按你想要的方式工作。 Following is only the modified version of the for loop. 以下仅是for循环的修改版本。 Rest stays the same. 休息保持不变。 The added/modified lines are highlighted by a comment 添加/修改的行由注释突出显示

for idx, i in enumerate(prices):
    s += i
    sums.append(s)
    if idx == n-1: # Added
        ave = (sums[idx]) / n  # Added 
        ma.append(ave)  # Added
    elif idx >= n: # modified
        ave = (sums[idx] - sums[idx-n]) / n
        ma.append(ave)
    else:
        ma.append(None) # removed extra variable m

The problem was that you were using the wrong variable as the index: 问题是您使用了错误的变量作为索引:

One major problem was that you were using 一个主要问题是你正在使用

if i >= n+1:

You should use: 应该使用:

if idx >= n+1:

Moreover, I added an if statement to take care of the average of the first three elements. 此外,我添加了一个if语句来处理前三个元素的平均值。

Now 现在

moving_average([2,3,4,5,8,5,4,3,2,1], 3)

gives the following output (you can round off later): 给出以下输出(您可以稍后舍入):

[None, None, 3.0, 4.0, 5.666666666666667, 6.0, 5.666666666666667, 4.0, 3.0, 2.0]

If you are ok using the standard library, this might help. 如果您可以使用标准库,这可能会有所帮助。 What you really need is a sliding window over your iterator. 你真正需要的是在迭代器上的滑动窗口。 You can use this function for that (this was based on grouper from itertools recipes): 您可以使用此功能(这是基于来自itertools食谱的grouper ):

from itertools import islice

def window(iterable, n=2):
    # window('123', 2) --> '12' '23'
    args = [islice(iterable, i, None) for i in range(n)]
    return zip(*args)

For the average you can use statistics.mean . 对于平均值,您可以使用statistics.mean The paddig part can be simply achieved by adding the average list with [None] * (n - 1) : paddig部分可以通过添加[None] * (n - 1)的平均列表来简单地实现:

from statistics import mean

def moving_average(prices, n):
    avgs = [mean(w) for w in window(prices, n)]
    padding = [None] * (n - 1)

    return padding + avgs

Sample usage: 样品用法:

>>> moving_average([2,3,4,5,8,5,4,3,2,1], 3)
[None, None, 3, 4, 5.666666666666667, 6, 5.666666666666667, 4, 3, 2]
>>> moving_average([1, 2, 3], 3)
[None, None, 2]
>>> moving_average([1, 2, 3], 1)
[1, 2, 3]
>>> moving_average([5, 10, 0], 2)
[None, 7.5, 5]

The reason why your program returned that 9-9 / 3 = 0 is negative indexing. 你的程序返回9-9 / 3 = 0是负索引。 When idx is 2 , sums[idx-n] is saying sums[-1] , which points at the last item of the list, 9 . idx2sums[idx-n]表示sums[-1] ,它指向列表的最后一项, 9 Understanding Python's slice notation could help explain that. 理解Python的切片表示法可以帮助解释这一点。

You could also solve this using list slicing to partition your input list smartly and calculate the avg over the list-partitions: 您还可以使用列表切片来解决此问题,以便巧妙地对输入列表进行分区并计算列表分区上的平均值:

def moving_average(data,window):
    """The partitions begin with window-1 None. Then follow partial lists, containing
       window-sized elements. We do this only up to len(data)-window+1 as the following
       partitions would have less then window elements."""

    parts = [None]*(window-1) + [ data[i:i+window] for i in range(len(data)-window+1)]
    #       The None's           The sliding window of window elements

    # we return None if the value is None else we calc the avg
    return [ sum(x)/window if x else None for x in parts] 

print( moving_average([2,3,4,5,8,5,4,3,2,1], 1) )
print( moving_average([2,3,4,5,8,5,4,3,2,1], 2) )
print( moving_average([2,3,4,5,8,5,4,3,2,1], 3) )

Output ( parts included as comment): 输出(包括注释的parts ):

# [[2], [3], [4], [5], [8], [5], [4], [3], [2], [1]]
[2.0, 3.0, 4.0, 5.0, 8.0, 5.0, 4.0, 3.0, 2.0, 1.0]

# [None, [2, 3], [3, 4], [4, 5], [5, 8], [8, 5], [5, 4], [4, 3], [3, 2], [2, 1]]
[None, 2.5, 3.5, 4.5, 6.5, 6.5, 4.5, 3.5, 2.5, 1.5]

# [None, None, [2, 3, 4], [3, 4, 5], [4, 5, 8], [5, 8, 5], [8, 5, 4], 
#              [5, 4, 3], [4, 3, 2], [3, 2, 1]]
[None, None, 3.0, 4.0, 5.666666666666667, 6.0, 5.666666666666667, 4.0, 3.0, 2.0]

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