将嵌套列表中的所有元素转换为整数

Question

I have a list with integers as strings so how can I convert it back

lst = ["['1','2']", "['2','4']", "['1','4']", "['1','5']", "['3','5']", "['3','4']"]

I tried to use a list comprehension

[j for j in i if j.isdigit() for i in lst ]

but it returns

['3', '3', '3', '3', '3', '3', '4', '4', '4', '4', '4', '4']

Desired output:

[[1,2],[2,4],[1,4],[1,5],[3,5],[3,4]]

Any help?

Answer 1

Use ast module.

Ex:

import ast

lst = ["['1','2']", "['2','4']", "['1','4']", "['1','5']", "['3','5']", "['3','4']"]
res = [list(map(int, ast.literal_eval(i))) for i in lst]
print(res)

Output:

[[1, 2], [2, 4], [1, 4], [1, 5], [3, 5], [3, 4]]

Answer 2

Naive solution:

>>> lst = ["['1','2']", "['2','4']", "['1','4']", "['1','5']", "['3','5']", "['3','4']"]
>>> [[int(x.strip("'")) for x in s[1:-1].split(',')] for s in lst]
[[1, 2], [2, 4], [1, 4], [1, 5], [3, 5], [3, 4]]

Answer 3

You can use ast module's literal_eval function and list comprehension

>>>[[int(j) for j in ast.literal_eval(i)] for i in lst]

[[1, 2], [2, 4], [1, 4], [1, 5], [3, 5], [3, 4]]

Answer 4

final_lst = []


for s in lst:
  sublist = []
  for item in eval(s):
     sublist.append(int(item))
  final_lst.append(sublist)

print(final_lst) 

Answer 5

you simply eval every list in the main list then parse every int inside sub lista

lst = ["['1','2']", "['2','4']", "['1','4']", "['1','5']", "['3','5']", "['3','4']"]
x = [[int(j) for j in eval(i)] for i in lst]
print (x)

output

[[1, 2], [2, 4], [1, 4], [1, 5], [3, 5], [3, 4]]